Let the speed for the first 12 mi be x mi/h, the speed for 18 mi was (x+4) mi/h
thus given that
time=distance/speed
the average time will be:
3=(12+18)/(x+x+4)
3=30/(2x+4)
solving for x we get
3(2x+4)=30
6x+6=30
6x=24
x=4 mi/hr
Answer: 12 mi/hr
The answer is 1/2 cuz of simplyfing
Answer:
least to greatest: -5 and 1
Step-by-step explanation:
they represent the zeroes of the function and are sorted from least to greatest
The resolvent is:
x = (- b +/- root (b2 - 4ac)) / 2a
To apply it we must have a polynomial of the form:
ax2 + bx + c = 0
Where,
One side of the equation is zero.
The polynomial must be only grade 2.
The coefficient a must be different from zero.
Answer:
options: B, C, D are correct
Answer:
Step-by-step explanation:
A. Rate of change (or slope) is $50
The initial tutoring fee starts out at $1200 in 2005
How do you know? Each year the cost goes up $50
2005 = $1200
2006 = $1250
2007 = $1300
2008 = $1350
B. y=50x+b
