2 years ago

Please helpppp

Mathematics

2 answers:

user100 [1]2 years ago

5 0

Answer:

its c

Step-by-step explanation:

notsponge [240]2 years ago

4 0

Answer:

Option C 7 is your answer ☺️☺️☺️

You might be interested in

8n+2=18? Show Your Work.

Yuri [45]

18 - 2 = 16
8n = 16
Divide
N = 2

7 0

3 years ago

Read 2 more answers

Evaluate the limit assuming that limx→−5f(x)=17limx→−5f(x)=17 and limx→−5g(x)=22limx→−5g(x)=22. (use symbolic notation and fract

Gemiola [76]

In this question it is given that

$\lim_{x->-5}f(x)=17, \lim_{x->-5}g(x)=22$

And we have to find the value of the given limit

$\lim_{x->-5}(23f(x)+3g(x))$

Using properties of limit, first we separate the two functions, that is

$23\lim_{x->-5}f(x)+3\lim_{x->-5}g(x)$

Substituting the values of the given limit,

$23(17)+3(22)=457$

3 0

3 years ago

Find the area of a cylinder of radius 4 cm and height 5 cm

olga55 [171]

Answer:

226.19cm^2

Step-by-step explanation:

Total surface area of cylinder = 2πr(r + h).

4 0

1 year ago

Read 2 more answers

In the function f(x) = 225 - 31.4558 In, x represents the

KengaRu [80]

Answer:

Step-by-step explanation:

8 0

3 years ago

Blue Cab operates 15% of the taxis in a certain city, and Green Cab operates the other 85%. After a nighttime hit-and-run accide

NikAS [45]

Answer: The required probability is 0.414.

Step-by-step explanation:

Since we have given that

Probability of taxis in a certain city by Blue Cab P(B)= 15%

Probability of taxis by Green Cab P(G) = 85%

Let A be the event that eyewitness said that vehicle was blue.

P(A|B)=0.80

P(A|G)=0.80

P(A'|B)=0.20=P(A'|G)

Using the "Bayes theorem":

Probability that the taxi at fault was blue is given by

$=\dfrac{P(B).P(A|B)}{P(B).P(A|B)+P(G).P(A'|G)}\\\\=\dfrac{0.15\times 0.8}{0.15\times 0.8+0.85\times 0.2}\\\\=\dfrac{0.12}{0.12+0.17}\\\\=\dfrac{0.12}{0.29}\\\\=0.414$

Hence, the required probability is 0.414.

8 0

2 years ago