Answer:
see explanation
Step-by-step explanation:
We require 2 equations with the recurring part after the decimal point.
Let x = 0.555..... → (1)
Multiply both sides by 10, then
10x = 5.555..... → (2)
Subtract (1) from (2) thus eliminating the recurring decimal
(10x - x) = (5.5555 - 0.5555 ), that is
9x = 5 ( divide both sides by 9 )
x = 
Answer:
7/13
Step-by-step explanation:
Arrange the numbers so that the number of girls in year 10 is the numerator, and the total number of girls is the denominator. (140/260) Simplify this by dividing both numbers by 20.
6x + (-9) or 6x - 9
Try looking at the terms for the same things. Such as the variable like X and the negatives add together and make a negative
Answer:
The correct option is SSS (Side-Side-Side) Theorem
Step-by-step explanation:
The question is incomplete because the diagrams of ΔLON and ΔLMN are not given. I have attached the diagram of both triangles below for better understanding of the question.
Consider the diagram attached below. We have to find the congruence theorem which can be used to prove that ΔLON ≅ ΔLMN
We can see in the diagram that both triangle have a common side that is LN. It means 1 side of both triangles is congruent because LN≅LN
Consider the sides ON and MN. Both side have a single bar on them, which means that it is given that both of these side are congruent. Hence ON≅MN
Consider the sides LO and LM. Both side have a double bars on them, which means that it is given that both of these side are also congruent. Hence LO≅LM
SSS theorem states that if all sides of the triangles are congruent, then the triangles themselves are also congruent, which is the same case in this question
Answer:
<u>Option 1) x ≥ 0.5</u>
Step-by-step explanation:
<u>The given inequality is </u>: 2(4x - 3) ≥ -3(3x) + 5x
<u>And the options are:</u>
1) x ≥ 0.5
2) x ≥ 2
3) (–∞, 0.5]
4) (–∞, 2]
==============================
So, the solution is as following:
2(4x - 3) ≥ -3(3x) + 5x
8x - 6≥ -9x + 5x
8x + 9x - 5x ≥ 6
12 x ≥ 6
x ≥ 6/12
x ≥ 0.5
The answer is option 1) x ≥ 0.5