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natta225 [31]
3 years ago
12

5 + 7 x 4 – (11 + 6)

Mathematics
2 answers:
NemiM [27]3 years ago
7 0
You have to use bidmas first you do bracket so it’s 17 then you do multiple which is 28 then 28+5 is 33 then 33-17 is 16 =16
satela [25.4K]3 years ago
3 0

Answer:16

Step-by-step explanation:

Start with whats inside (11+6) (17) then you will multiply 7 and 4 = 28+5 =33 then back to 17,,,, 33-17=16

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Help please quickly
nadezda [96]
0.001 x 425 = .425

answer C. $0.425
3 0
3 years ago
Read 2 more answers
What is the justification for the first step in proving the formula for factoring the sum of cubes?
Anna11 [10]

Explanation:

The formula isnt correctly written, it should state:

a^3+b^3 = (a+b)(a^2-ab+b^2)

You have to start from (a+b)(a^2-ab+b^2)  and end in a³+b³. On your first step, you need to use the distributive property.

(a+b)(a^2-ab+b^2) = a*(a^2-ab+b^2) + b*(a^2-ab+b^2)

This is equal to

a*a^2-a*(ab) + a*b^2 + b*a^2-b*(ab) + b*b^2 = a^3 - a^2b + ab^2 +ba^2 -b^2a +b^3

Note that the second term, -a²b, is cancelled by the fourth term, ba², and the third term, ab², is cancelled by the fifht term, -b²a. Therefore, the final result is a³+b³, as we wanted to.

5 0
4 years ago
I am not sure if this is right can someone check it ASAP please
NikAS [45]

Answer:

x=10

Step-by-step explanation:

3(4x-12) = 84

Divide each side by 3

3/3(4x-12) = 84/3

4x-12 =28

Add 12 to each side

4x-12+12 = 28+12

4x= 40

Divide each side by 4

4x/4 = 40/4

x = 10

6 0
3 years ago
Mr. Wallace gave a test to his math classes. He created a histogram that showed the frequency of As, Bs, and Cs. He labeled the
Gennadij [26K]

Answer:

D

Step-by-step explanation:

I got it right on Khan Academy

3 0
3 years ago
The sum of two consecutive odd integers is at least 16
elena-14-01-66 [18.8K]
Odd integers are represented by 2n+1 where n is a whole number

consecutive odd are 2 apart so
they are 2n+1 and 2n+1+2

the sum of them is at least 16
2n+1+2n+1+2<u>></u>16
4n+4<u>></u>16
minus 4
4n<u>></u>12
divide 4
n<u>></u>3
sub back

2n+1 and 2n+3
2(3)+1 and 2(3)+3
6+1 and 6+3
7 and 9

they have to be at least 7 and 9
5 0
4 years ago
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