All categories

3 years ago

Math help! plsss on these questions

Mathematics

1 answer:

likoan [24]3 years ago

5 0

1.)-2v-7=-23
-2v=-16
v=8
2.)x/3-10=-12
x/3-10=-12
x/3=-2
x=-6
3.) x/4+10=14
x/4=4
x=16

You might be interested in

801 round to the nerest ten

jolli1 [7]

801 rounded to the nearest ten would be 811

8 0

3 years ago

Read 2 more answers

What is the value of x?

djverab [1.8K]

Answer:

x = 55°

Step-by-step explanation:

Hello!

The sum of angles in a triangle is 180°.

To solve for x, we have to subtract the given angles from 180°.

<h3>Solve for x</h3>

180° = ∠1 + ∠2 + ∠x
180° = 75° + 50° + x°
180° - 75° - 50° = x°
55° = x°

The value of x is 55°.

6 0

2 years ago

Read 2 more answers

I need help please. Trying to get my HS diploma. I did not graduate :(

grigory [225]

The graph of f(x) + 1 is the graph in the option C.

<h3>Which is the graph of f(x) + 1?</h3>

For a given function f(x), a vertical translation is written as:

g(x) = f(x) + N

If N > 0, then the translation is upwards.
If N < 0, then the translation is downwards.

Here we have g(x) = f(x) + 1, so we have a translation of 1 unit upwards, the graph of f(x) + 1 is the graph of f(x) but translated one unit upwards.

From that, we conclude that the correct option is C.

If you want to learn more about translations:

brainly.com/question/24850937

#SPJ1

3 0

2 years ago

Obtain the general solution to the equation. (x^2+10) + xy = 4x=0 The general solution is y(x) = ignoring lost solutions, if any

alukav5142 [94]

Answer:

$y(x)=4+\frac{C}{\sqrt{x^2+10}}$

Step-by-step explanation:

We are given that a differential equation

$(x^2+10)y'+xy-4x=0$

We have to find the general solution of given differential equation

$y'+\frac{x}{x^2+10}y-\frac{4x}{x^2+10}=0$

$y'+\frac{x}{x^2+10}y=4\frac{x}{x^2+10}$

Compare with

$y'+P(x) y=Q(x)$

We get

$P(x)=\frac{x}{x^2+10}$

$Q(x)=\frac{4x}{x^2+10}$

I.F= $e^{\int\frac{x}{x^2+10} dx}=e^{\frac{1}{2}ln(x^2+10)}$

$e^{ln\sqrt(x^2+10)}=\sqrt{x^2+10}$

$y\cdot \sqrt{x^2+10}=\int \frac{4x}{x^2+10}\times \sqrt{x^2+10} dx+C$

$y\cdot \sqrt{x^2+10}=\int \frac{4x}{\sqrt{x^2+10}}+C$

$y\cdot \sqrt{x^2+10}=4\sqrt{x^2+10}+C$

$y(x)=4+\frac{C}{\sqrt{x^2+10}}$

6 0

3 years ago

What is the area of this trapezoid? Please help me

jenyasd209 [6]

Answer:

192

Step-by-step explanation:

both triangles are 12 in and the square is 168

so 12+12+168= 192in

3 0

3 years ago