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3 years ago

In a school with 2,000 students, a random sample of 120 students were asked which fruit is their favorite. Their

Mathematics

2 answers:

alex41 [277]3 years ago

7 0

567 students would pick orange

Maslowich3 years ago

5 0

567 students would pick orange

You might be interested in

Which choice is equivalent to the product below?

Anna [14]

Answer:

4√7

Step-by-step explanation:

it's correct I m pretty sure but dat

5 0

2 years ago

Which of the following is true of the data set represented by the box plot max at 35

Bezzdna [24]

Though the box plot is not given, the truth about the data set represented by the box plot is removing the outliers would not affect the median.

A box plot gives a graphical (rectangular) representation of statistical data based on the following five values: minimum, first quartile, median, third quartile, and maximum.

Essentially, a box plot has the following five data descriptions:

The leftmost whisker, showing the minimum value.
The rightmost whisker, showing the maximum value.
The leftmost line, showing the first quartile.
The middle line, showing the median or the second quartile.
The last line shows the third quartile.

Thus, the truth about the data set represented by the box plot is removing the outliers would not affect the median.

Learn more about the box plot at brainly.com/question/14277132

3 0

2 years ago

Can someone help me with this question please

postnew [5]

Answer:

which ones do you need??

7 0

3 years ago

Could someplease explain the whole problem? For the first part my the answer I got was x= .618, -.618, and <img src="https://tex

algol13

9514 1404 393

Answer:

a) x = (√5 -1)/2 ≈ 0.618034

b) 1/x = (√5 +1)/2 ≈ 1.618034

Step-by-step explanation:

Given:

x/(1 -x) = 1/x

Find:

Exactly, and as a decimal approximation, ...

a) x, using the quadratic formula

b) 1/x

Solution:

a) We can multiply the given equation by x(1 -x) to obtain ...

x² = 1 -x

x² +x -1 = 0 . . . . . . add x-1

The coefficients for use in the quadratic formula are a=1, b=1, c=-1. The solution using the quadratic formula is ...

$x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-1\pm\sqrt{1^2-4\cdot1\cdot(-1)}}{2\cdot1}=\dfrac{-1\pm\sqrt{5}}{2}$

We are only interested in the positive solution, which is ...

$\boxed{x=\dfrac{\sqrt{5}-1}{2}\approx0.618034}$

b) The quadratic we developed in the first part can be rearranged like this:

x² +x = 1 . . . . . . add 1 to both sides

x(x +1) = 1 . . . . . factor out x

x +1 = 1/x . . . . . .divide by x

Then to find the value of 1/x, we simply need to add 1 to the value of x we have:

$\dfrac{1}{x}=\dfrac{\sqrt{5}-1}{2}+1=\dfrac{\sqrt{5}-1}{2}+\dfrac{2}{2}=\dfrac{\sqrt{5}-1+2}{2}\\\\\boxed{\dfrac{1}{x}=\dfrac{\sqrt{5}+1}{2}\approx1.618034}$