Remark
You know the most about the trip on the way back and the total of the two trips.
Way Back
r = 30 mph
d = distance traveled
t = t - 1 where t = the time to go there which we know nothing about
Total Distance
2d = 25 mph * (t + t - 1)
2d = 25 * (2t - 1)
2d = 50t - 25 Divide by 2
2d = 50t/2 - 25/2
d = 25t - 12.5
Equation coming back
d = 30*(t - 1)
d = 30t - 30
Comment
Since the distances are the same, equate them.
Solution
25t - 12.5 = 30t - 30 Subtract 25t from both sides
25t - 25t -12.5 = 30t - 25t - 30 Combine like terms
-12.5 = 5t - 30 Add 30 to both sides
-12.5 + 30 = 5t - 30 + 30 Combine
17.5 = 5t Divide by 5
17.5/5 = t Divide and Switch
t = 3.5
t is the time going there
t - 1 is the time coming back
Total time = 2*t - 1 = 2*3.5 - 1 = 6
The total time is 6 hours. Answer
"A student" doesn't register for 46,140 credits, unless he wants to be very very busy.
If ALL of the students on campus register for 46,140 credits, then many colleges
would estimate the number of full-time students by using the formula
f = n / 15 = 46,140 / 15 = <u>3,076</u> students.
That's not the formula for 'n'. 'n' is the total number of credits for the semester,
and the question tells you what 'n' is. Knowing 'n', the formula helps you find 'f'.
Answer:
x=10.7
Step-by-step explanation:
Our proportion is
x/4=8/3
We can cross multiply to solve.
This is where you multiply one fraction's numerator with the other fraction's denominator and vice versa.
x*3=4*8
3x=32
Divide both sides by 3.
x=10.6666666667
Round.
x=10.7
I say its 11. Since the distance between the two points is 11.
