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attashe74 [19]
3 years ago
12

Wally Beige has painted a rectangular mural that is 7 ft tall and 11 ft wide. He plans to paint a border of equal width all the

way around the outside of the mural. To end up with a border that has an area of 88 square ft, find the width of the border.
Mathematics
1 answer:
4vir4ik [10]3 years ago
7 0

Answer:

Width = 4ft

Step-by-step explanation:

Area of the rectangular mural = Length × Breadth

7 ft tall and 11 ft wide.

(11 - 2W)(7 - 2W) = 88

77 -22W - 14W + 4W² = 88

77 -36W + 4W² = 88

4W² - 36W + 77 - 88

= 4W² - 36W - 11

W = 4ft

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LiRa [457]

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
A random variable r is normally distributed with a mean of 7 and a standard deviation of 1.5. Find the value of w so that P (8.8
a_sh-v [17]

Answer:

The answer is explained below

Step-by-step explanation:

Given that:

mean (μ) = 7 and standard deviation (σ) = 1.5.

The z score is used in statistic used to measure the number of standard deviation by which the raw score is above or below the mean value. It is given by:

z=\frac{x-\mu}{\sigma}, where\ x\ is\ the \ raw\ score

To find the Probability that x < 8.8, we first find the z score using:

z = \frac{x-\mu}{\sigma}=\frac{8.8-7}{1.5}=1.2

From the z tables, P(x < 8.8) = P(z < 1.2) = 0.8849 = 88.49%

4 0
3 years ago
Discrete R.V. Assume a student shows up for EGR 280 completely unprepared and the instructor gives a pop quiz. Assume there are
Tom [10]

Answer:

a) p=0.2

b) probability of passing is 0.01696

.

c) The expected value of correct questions is 1.2

Step-by-step explanation:

a) Since each question has 5 options, all of them equally likely, and only one correct answer, then the probability of having a correct answer is 1/5 = 0.2.

b) Let X be the number of correct answers. We will model this situation by considering X as a binomial random variable with a success probability of p=0.2 and having n=6 samples. We have the following for k=0,1,2,3,4,5,6

P(X=k) = \binom{n}{k}p^{k}(1-p)^{n-k} = \binom{6}{k}0.2^{k}(0.8)^{6-k}.

Recall that \binom{n}{k}= \frac{n!}{k!(n-k)!} In this case, the student passes if X is at least four correct questions, then

P(X\geq 4) = P(X=4)+P(X=5)+P(X=6)=\binom{6}{4}0.2^{4}(0.8)^{6-4}+\binom{6}{5}0.2^{5}(0.8)^{6-5}+\binom{6}{6}0.2^{6}(0.8)^{6-6}= 0.01696

c)The expected value of a binomial random variable with parameters n and p is E[X] = np. IN our case, n=6 and p =0.2. Then the expected value of correct answers is 6\cdot 0.2 = 1.2

5 0
3 years ago
Mr. Sanchez buys 5 shirts and 3 ties for $34. At
Nastasia [14]

Answer:

y < x + 7

Step-by-step explanation:

7 0
3 years ago
Please help___________​
kramer

Answer:

Step-by-step explanation:

Let's do the obvious things first.

Right rectangle

w = 11

L = 17

Formula

Area = L * W

Area = 11 * 17

Area =                                                187

Left rectangle

W = 8

L = 11

Area = 8 * 11=                                      88

Middle Rectangle

W = 11

L = 15

Area = 11 * 15                                    165

Now we come to the triangles. It's not obvious what to do with them. You have to infer that one of the lets is 8 and the other is 15. You get the 8 from the width of the left rectangle (see above.)

There are 2 triangles

Area = 2 * 1/2 * l1 * l2

Leg 1 = 8

Leg2 = 15

Area = 2 * 1/2 (8 * 15)

Area =               <u>                            120 </u>

Total  = 120 + 165 + 88 + 187 =    560

Unless you have an  E answer that is 560, my answer does not agree with any of the given answers. I would suggest that you ask your teacher how it is done. My method is correct.

4 0
2 years ago
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