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Nikitich [7]
3 years ago
7

Please answer this correctly

Mathematics
2 answers:
Montano1993 [528]3 years ago
7 0
The answer to that question is 97
Taya2010 [7]3 years ago
4 0

Answer:

Step-by-step explanation:

area = Area of rectangle 1 + area of rectangle 2 + area of rectangle 3 + area of triangle

=5 * 12 + 5*5 + 2*3 + (1/2)* 4 * 3

= 60 + 25 + 6 +6

= 97

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Task: E = mc2
Afina-wow [57]

Answer:

$c=\left(\frac{E}{m} \right)^{\frac{1}{2} }$

Step-by-step explanation:

E = mc^2

$c^2=\frac{E}{m} $

$c=\sqrt{\frac{E}{m} } $

or

$c=\left(\frac{E}{m} \right)^{\frac{1}{2} }$

3 0
4 years ago
What percent of 200 is 0.5?
OleMash [197]
<span>Question: What percent of 200 is 0.5?
Solutions and discussions:
=> 200 is the 100% value of the numbers
=> 0.5 is the number in which we need to find the percentage value of it in 200.
How to solve. Simply follow the formula
=> 0.5 / 200 = 0.0025 – this is the to get the decimal value of the number that we will be converting to percentage.
=> 0.0025 * 100% = 0.25%
Therefore 0.5 is 0.25% of 200.

</span>



3 0
4 years ago
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Simplify this expression
Gnesinka [82]
It’s A!! hope that helped
5 0
3 years ago
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If sin(2x) = cos(x + 30"), what is the value of x?<br> 20°<br> 30°<br> 500<br> 1100
ivanzaharov [21]

Answer:

2x=(x+30)

2x+x=30

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7 0
3 years ago
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When two equal forces are inclined at an angle 2a their resultant is twice as great as
swat32

Step-by-step answer:

Referring to the attached diagram, the resultant of two forces each with magnitude F and inclined to each other at 2a equals

Ra = 2Fcos(a) ..............................(1)

Similarly, the resultant of two forces each with magnitude F and inclined to each other at 2b equals

Rb = 2Fcos(b)..............................(2)

We are given that

Ra = 2Rb  ....................................(3)

Substitute (1) & (2) in (3) gives

2Fcos(a) = 2(2Fcos(b))

Expand

2Fcos(a) = 4Fcos(b)

Simplify

cos(a) = 2 cos(b)   QED

Note: Please note that you might have a faster response if you posted this question in the physics or the (new) Engineering section.

Have a nice day!

5 0
3 years ago
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