For this problem, we are given a parallelogram with a diagonal drawn, inside it there are markings for a few angles. We need to determine the unknown angles.
Opposite sides of a parallelogram are parallel, this means we can treat the diagonal as a transversal line that crosses two parallel lines. Since this is the case, the angles 33º and xº are alternate interior angles and have the same length:

The opposite angles in a parallelogram are congruent, therefore:

The sum of internal angles is 360º, therefore we have:

The value of x is 33º, the value of y is 38º and the value of z is 109º.
It is a supplementary angle. D because the add up to 180.
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Answer:
No, A″C″B″ is located at A″(1, 1), C″(4, 3), and B″(1, 5)
Step-by-step explanation:
Line AB is horizontal, so reflection across the x-axis maps it to a horizontal line. Then rotation CCW by 90° maps it to a vertical line. The composition of transformations cannot map the figure to itself.
A reasonable explanation is the last one:
No, A″C″B″ is located at A″(1, 1), C″(4, 3), and B″(1, 5)