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hjlf
3 years ago
15

Help me please please!!!!!!!!

Mathematics
1 answer:
vova2212 [387]3 years ago
6 0

Answer:

a

Step-by-step explanation:

The circumference (C) of a circle is calculated as

C = 2πr ( r is the radius ) , then

C = 2π × 20 = 40π

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Pleeaaassseeeees help,
sattari [20]

Hey there!

Since you probably have better things to do, your answer would be A: π(3)²

To back up my answer, the formula to find the area of a circle is π · R² where R = Radius. In that formula then, you just plug everything in. Since the radius is 3, you would put 3 into the "( )". Finally, just plug the rest of the equation in!

<em>I'm open to any question or comment!</em>

<em>God Bless!</em>

<em>-X8lue83rryX</em>

5 0
3 years ago
A company manufactures aluminum mailboxes in the shape of a box with a half-cylinder top. The company will make 1960 mailboxes t
MaRussiya [10]

Answer:

  7088 m²

Step-by-step explanation:

The area of the half-cylinder is half the area of a cylinder with the same dimensions. This half-cylinder has a radius of 0.3 m and a length of 0.8 m, so its area is ...

  A = πr(r +l) = π(0.3 m)(0.3 m+0.8 m) = 0.33π m² ≈ 1.0362 m²

The area of the bottom part of the box is the sum of its lateral area and its base area.

  lateral area = Ph = (2(0.6m +0.8m))(0.75 m) = 2.1 m²

  base area = lw = (0.8 m)(0.6 m) = 0.48 m²

The total area is then ...

  total area = half-cylinder area + lateral area + base area

  = 1.0362 m² +2.1 m² +0.48 m²

  = 3.6162 m²

__

The area for 1960 mailboxes will be 1960 times this area, or ...

  area for week's production = 1960 × 3.6162 m² = 7087.752 m²

It will take about 7088 square meters of aluminum to make these mailboxes.

5 0
3 years ago
Area for a kite<br> I don’t know how to find the area pls help
dusya [7]

Answer:

63.966

Step-by-step explanation:

Area of a kite is

\frac{pq}{2}

where p and q are the diagonals.

The horinzontial diagonal is 8.

We need to find the vertical diagonal length.

The top triangle diagonal measure is

{4}^{2}  +  {x}^{2}  =  {7}^{2}

16 +  {x}^{2}  = 49

{x}^{2}  = 33

x =  \sqrt{33}

The bottom triangle diagonal measure is

{4}^{2}  +  {x}^{2}  =  {11}^{2}

1 6 +  {x}^{2}  = 121

{x}^{2}  = 105

x =  \sqrt{105}

Add the two diagonals.

\sqrt{105}  +  \sqrt{33}

Substitute this in for the formula

\frac{8 \times ( \sqrt{105}  + \sqrt{33}  }{2}

Which simplified gu

Ives us

63.966

Round if neededd.

7 0
3 years ago
you are selling pandesal to raise money for a school field trip. Pandesal with cheese cost 8.00 pesos and ube pandesal cost 9.00
Lera25 [3.4K]

Answer:

Let's define:

C = number of pandesal with cheese that you sell

U = number of pandesal with ube that you sell.

If you sell these numbers of each, the total profit you get is:

C*8.00 pesos + U*9.00 pesos.

And yo want to get at least 180 pesos, then:

C*8.00 pesos + U*9.00 pesos ≥ 180 pesos.

And you also want to sell two of each, then:

C ≥ 2

U ≥2

So the system of inequalities is:

C*8.00 pesos + U*9.00 pesos ≥ 180 pesos.

C ≥ 2

U ≥2

If U is on the x-axis, and C is on the y-axis, then the graph is: (where the region at the right of the vertical line should be shaded)

6 0
2 years ago
Pls help 25h²- 16t² factorise it​
noname [10]

Answer:

(5h-4t)(5h+4t)

Step-by-step explanation:

25h² - 16t²

adding  and subtracting 20ht from it        (√25 and √16 = 5x4 = 20):

25h² + 20ht - 20ht -16t²

factor:

(5h-4t)(5h+4t)

8 0
2 years ago
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