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Pavlova-9 [17]
3 years ago
14

5t-shirts and a hat costs £83.00,2 t-shirts and a hat costs £38.00.a)how much does a t-shirt cost?

Mathematics
1 answer:
Sergio039 [100]3 years ago
7 0

Answer:

$9 per t-shirt

Step-by-step explanation:

First you subtract the cost of the hats from the TOTAL cost of the the T-shrits and the hat.

$83.00-$38.00= $45

Now that you just have the shirts WITHOUT the hat, which is why we subtracted the $38.00, we have to devide. You devide 45 by the number of shirts.

45/5=9

$9 per T-shirt.

Hope this helps

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Geometry - Law of Sines question #17. Please help, I am stuck.
Flauer [41]

By the law of sines, m∠<em>EFG</em> is such that

sin(m∠<em>EFG</em>) / (8 in.) = sin(m∠<em>G</em>) / (7.5 in)

so you need to find m∠<em>G</em>.

The interior angles to any triangle sum to 180°, so

m∠<em>DEG</em> = m∠<em>D</em> + m∠<em>G</em> + 43°

m∠<em>DEG</em> + m∠<em>D</em> + m∠<em>G </em>= 2 (m∠<em>D</em> + m∠<em>G</em>) + 43°

180° = 2 (m∠<em>D</em> + m∠<em>G</em>) + 43°

137° = 2 (m∠<em>D</em> + m∠<em>G</em>)

68.5° = m∠<em>D</em> + m∠<em>G</em>

But ∆<em>DEG</em> is isosceles, so m∠<em>D</em> = m∠<em>G</em>, which means

68.5° = 2 m∠<em>G</em>

34.25° = m∠<em>G</em>

<em />

Then

sin(m∠<em>EFG</em>) = (8 in.) sin(34.25°) / (7.5 in)

m∠<em>EFG</em> ≈ sin⁻¹(0.600325) ≈ 36.8932°

4 0
3 years ago
The state fair is a popular field trip destination. This year the senior class at High School A and the senior class at High Sch
SSSSS [86.1K]

Answer:

The number of students in each van = 14

The number of students in each bus = 43

Step-by-step explanation:

Let the number of students that can fill a van be v.

Let the number of students that can fill a bus be b.

The senior class at High School A rented and filled 13 vans and 9 buses with 569 students.

13 vans will have (13v) students

9 buses will have (9b) students

13v + 9b = 569

High School B rented and filled 14 vans and 3 buses with 325 students

14 vans will have (14v) students.

3 buses will have (3b) students.

14v + 3b = 325

Combining these two simultaneous equations

13v + 9b = 569

14v + 3b = 325

Solving simultaneously,

v = 14 students.

b = 43 students.

Hope this Helps!!!

5 0
3 years ago
Write an expression with a negative exponent that has a value between 0 and 1/2
aliya0001 [1]
<span>Exponent is a number used to express shorter equation; it is a number that says how many times you are going to multiply the base number.
</span><span>
Exponents have several laws, here are some:
=> x^1 = x
=> x^0 = 1
=> x^-1 = 1/x
=> x^m x^n = X^m+n
=> x^m/x^n = x^m-n

And since we were asked to write an expression with a negative exponent that has a value between 0 and ½
=> 2^ -2 = ½

</span>



4 0
3 years ago
In triangle ABC shown below, DE is parallel to AC. The following two-column proof with missing statements and reasons proves tha
lianna [129]

Answer:

The correct option is;

C. 3. ∠BDE ≅∠BAC, Corresponding Angles Postulate 4. ∠B ≅ ∠B Reflexive Property of Equality

Step-by-step explanation:

The two column proof can be written as follows;

Statement,                         Reason

1. \overline{DE} \parallel \overline{AC},                           Given

2. \overline {AB} is a transversal ,         Conclusion from statement 1.

We note that ∠BDE  and ∠BAC are on the same side of the transversal relative to the parallel lines, and are therefore, corresponding angles.

Therefore, we have;

3. ∠BDE ≅∠BAC,                 Corresponding Angles Postulate

Also

4. ∠B ≅ ∠B,                           Reflexive Property of Equality

In the two triangles, ΔABC and ΔDBE, we have ∠BDE ≅∠BAC and ∠B ≅ ∠B,

From ∠BDE + ∠B + ∠BED = 180°

∠BAC + ∠B +  ∠BCA = 180°

Therefore, ∠BED = ∠BCA Substitution property of equality

Which gives;

5, ΔABC ~ ΔDBE,          Angle Angle Similarity Postulate

6. BD/BA = BE/BC,      Converse of the Side-Side-Side Similarity Theorem

5 0
3 years ago
Help me,,.,,.,.,,,,,..,,,,..
Stella [2.4K]

Answer:

90

Step-by-step explanation:

that's a right angle

4 0
3 years ago
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