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xxMikexx [17]
3 years ago
11

-3r + 18 = 15r please help!!

Mathematics
2 answers:
Luba_88 [7]3 years ago
8 0

Answer:

r = 1

Step-by-step explanation:

Step 1: Write equation

-3r + 18 = 15r

Step 2: Solve for <em>r</em>

  1. Add 3r to both sides: 18 = 18r
  2. Divide both sides by 18: 1 = r
  3. Rewrite: r = 1

Step 3: Check

<em>Plug in r to verify it's a solution.</em>

-3(1) + 18 = 15(1)

-3 + 18 = 15

15 = 15

VLD [36.1K]3 years ago
7 0

Step-by-step explanation:

- 3r - 15r = -18 .... Moved variables to one side and constants to the other

- 18r = - 18 ..... Simplified

r = 1 ..... Divided to isolate the r

Check:

Plug in 1 for r

-3(1) +18 = 15(1)

- 3+18 = 15

15 = 15 .... Therefore 1 is correct

Answer is 1

Hope this helps!

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adoni [48]

Complete Question

A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of parts had a mean of 1.6 millimeters with a standard deviation of 0.03 millimeters. what standard deviation will be needed to achieve a process capability index f 2.0?

Answer:

The value required is  \sigma =  0.0133

Step-by-step explanation:

From the question we are told that

   The upper specification is  USL  =  1.68 \ mm

    The lower specification is  LSL  = 1.52  \  mm

     The sample mean is  \mu =  1.6 \  mm

     The standard deviation is  \sigma =  0.03 \ mm

Generally the capability index in mathematically represented as

             Cpk  =  min[ \frac{USL -  \mu }{ 3 *  \sigma }  ,  \frac{\mu - LSL }{ 3 *  \sigma } ]

Now what min means is that the value of  CPk is the minimum between the value is the bracket

          substituting value given in the question

           Cpk  =  min[ \frac{1.68 -  1.6 }{ 3 *  0.03 }  ,  \frac{1.60 -  1.52 }{ 3 *  0.03} ]

=>      Cpk  =  min[ 0.88 , 0.88  ]

So

         Cpk  = 0.88

Now from the question we are asked to evaluated the value of  standard deviation that will produce a  capability index of 2

Now let assuming that

         \frac{\mu - LSL  }{ 3 *  \sigma } =  2

So

         \frac{ 1.60 -  1.52  }{ 3 *  \sigma } =  2

=>    0.08 = 6 \sigma

=>     \sigma =  0.0133

So

        \frac{ 1.68  - 1.60 }{ 3 *  0.0133 }

=>      2

Hence

      Cpk  =  min[ 2, 2 ]

So

    Cpk  = 2

So    \sigma =  0.0133 is  the value of standard deviation required

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Answer:

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Step-by-step explanation:

Please see attached picture for full solution.

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Answer:

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Step-by-step explanation:

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