Answer:
The areas are equal.
Step-by-step explanation:
Let the first rectangle be R and
the second rectangle be R'.
Sine R and R' are identical, their lengths are equal and their breadths are equal.
So, if Inga divided each into equal parts, then each part of both rectangles are equal.
Hence, the colored parts of both rectangles are equal.
Side = 8m
He increases length by 2m and reduces width by 2m
(a.) New dimensions will be -
Length = 10m and Width = 6m
(b.) Area = length x breadth (or width)
here we will use the special product (x+y) (x-y)
length = (x+y) and width = (x-y)
area = (8+2) x (8-2)
8^(2) - 2^(2)
= 60
We'll use the following properties of sine and cosine to prove this:



Then it's just a matter of filling it in...
sin20sin40 * sin60sin80 = 1/2(cos20 - cos60) * 1/2 (cos20 - cos140) =
1/8( cos40 + 1 - cos160 - cos120 - cos40 - cos80 + cos80 + cos200) =
1/8(1 - cos160 - cos120 + cos200) =
1/8(1 - cos160 - cos120 + cos160) =
1/8(1 - cos120 ) = 1/8( 1 + 1/2 ) = 3/16
Answer:
The answer is 83/4
Step-by-step explanation:
5 1/4+15.5
21/4+15.5
Taking LCM
21/4+15.5*4/1*4
21/4+62/4
83/4