Answer:
the answer is 20
Step-by-step explanation:
The answer is 20. The rule of math, for this math problem, is that you do the multiplication first and then solve. Order of operations is "PEMDAS," which explained is by following these rules: Parentheses First.
Answer:
life insurance is a type n other are together called as non-life insurance.
Answer:
a) Vertex is at (-3, -1)
b) y-intercept is at (0,8)
c) x intercept is at (-4,0) and (-2,0)
d) x=-3
Step-by-step explanation:
We know the vertex is the lowest or highest part of a parabola meaning all the points are reflected across. It is the only y value without a matching pair
E.x. -1 and 1, -3 and 3
The only point without a corresponding y value is (-3,-1) therefore the vertex is at (-3,-1)
The y-intercept is where the parabola meets the y axis or the x value is equal to 0, we just have to find when x = 0 to find the y intercept
y intercept: (0,8)
For the x intercept's it is just the reverse, you need to find where the parabola crosses the x axis or when y = 0
x intercept 1:(-4,0)
x intercept 2: (-2,0)
The axis of symmetry is also the x coordinate of the vertex which is 3 so
x = 3
Answer:
tetrahedral
Step-by-step explanation:
According to the valence shell electron pair repulsion theory (VSEPR) the shape of a molecule is dependent on the number of electron pairs on the valence shell of the central atom in the molecule.
The predicted electron pair geometry may sometimes differ from the molecular geometry due to the presence of lone pairs and multiple bonds.
If we consider each nitrogen atom in N2 independently, we will notice that each nitrogen atom has four regions of electron density. Hence the electron pair geometry is tetrahedral.
First find the square root of 900 to get one side of the square, which is 30 inches.
Formula for area of a circle: pi times the radius(squared)
The radius is 15 because one side of the square equals the diameter of the circle. 15 squared is 225.
3.14x225=<u>706.5 inches squared
</u>I hope this helps, because I did not have a diagram of the problem, but this should be the answer if the circle is inscribed in the square.<u>
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