PART 1.
Going westward:
Distance: 2400 miles
Rate (this is speed): (450-wind_speed) mph
Time: distance / speed = 2400 / (450-wind speed)
Going eastward:
Distance: 2400 miles
Rate (this is speed): (450+wind_speed) mph
Time: distance / speed = 2400 / (450+wind speed)
PART 2
Formula for speed:
speed = distance / time
Now we solve this for time:
time = distance / speed
11h = 2400 / (450+-wind_speed)
+- sign is put because in one case wind increases speed of plane and in other case it decreases speed.
PART 3
To solve for wind_speed we start by rearranging formula so that we have wind_speed on left side:
(450+-wind_speed) = 2400 / 11
(450+-wind_speed) = 218mph
To fly this distance in 11h speed of plane must be 218mph.
The only way to get this solution is if we substract wind speed:
450-wind_speed = 218
wind_speed = 450-218 = 232mph
Answer:
4 x^2 - 1, this would be the answer to your question.
Answer:
Step-by-step explanation:
Given parameters:
Elevation of Town M = 282ft
Elevation of Town R = 679ft
Unknown:
How much higher is Town R than M = ?
Solution:
Town M lies below the sea level whereas Town R is above the sea level.
Graphically:
Town R 679ft
↑
↑
↑
↑
↔↔↔ Sea level
↓
↓
Town M 282ft
Town R is 282ft + 679ft higher than Town M = 961ft
