Answer:
hello 안녕하세요
Explanation:
mate I tried to write here but it says it's too much writing that why I attached a pic
BTW did u like that☺☺
Answer: Result:Enter the number of quarters in the jar: 4
Enter the number of dimes in the jar: 5
Enter the number of nickels in the jar: 2
Enter the number of pennies in the jar: 5
Total value is 1 dollars and 65 cents
Explanation: import java.util.Scanner;public class Coins { public static void main(String[]args) { int quarters, dimes, nickels, pennies; int total;Scanner scan = new Scanner (System.in);System.out.print("Enter the number of quarters in the jar: "); quarters = scan.nextInt();System.out.print("Enter the number of dimes in the jar: ");dimes = scan.nextInt(); System.out.print("Enter the number of nickels in the jar: ");nickels= scan.nextInt(); System.out.print("Enter the number of pennies in the jar: ");pennies = scan.nextInt(); int total_cents = 25*quarters + dimes*10 + nickels*5 + pennies;total =total_cents/100;total_cents = total_cents %100;System.out.println("Total value is " + total + " dollars and " + total_cents + " cents ");}}
Result:Enter the number of quarters in the jar: 4
Enter the number of dimes in the jar: 5
Enter the number of nickels in the jar: 2
Enter the number of pennies in the jar: 5
Total value is 1 dollars and 65 cents
<span>
If Johanna wants to label the x and y axes in an Excel chart, she should click anywhere on the chart, then click on the Layout tab. Under Labels, she should click on Axis Titles, and select the Secondary Horizontal Axis Title for x axis or <span>Secondary Vertical Axis Title for y axis. She should then select the text that is in the Axis Title box, and type the title name that she wants.</span></span>
Answer:
Explanation:
The following code is written in Python. It creates a method for each one of the questions asked and then tests all three with the same test case which can be seen in the picture attached below.
def alternating_list(lst1, lst2):
lst3 = []
for x in range(len(lst1)):
lst3.append(lst1[x])
try:
lst3.append(lst2[x])
except:
pass
if len(lst2) > len(lst1):
lst3.extend(lst2[len(lst1):])
return lst3
def reverse_alternating(lst1, lst2):
lst3 = []
if len(lst1) == len(lst2):
for x in range(len(lst1) - 1, -1, -1):
lst3.append(lst1[x])
lst3.append(lst2[x])
return lst3
def alternating_list_no_extra(lst1, lst2):
lst3 = []
max = 0
if len(lst1) > len(lst2):
max = len(lst2)
else:
max = len(lst1)
for x in range(max):
lst3.append(lst1[x])
try:
lst3.append(lst2[x])
except:
pass
return lst3
Answer:
heueururjrurh the best time to meet Vs t and get the use and may contain briy the best you had any y I have the same time ❤️ ry HR y regards Umesh he was a pleasure to have a great trip and u it
Explanation:
dgsisbsjdudb and I have a nice day best wishes for a few weeks back and I will send you an email from your NVR