Answer:
0
Step-by-step explanation:
f(0) = -2(0)²
= -2(0)
= 0
Answer : 100 meters 2:35/mile or 1:36/km 2:49/mile or 1:45/km
200 meters 2:35/mile or 1:36/km 2:52/mile or 1:47/km
400 meters 2:54/mile or 1:48/km 3:12/mile or 1:59/km
800 meters 3:23/mile or 2:06/km 3:48/mile or 2:21/km
1,500 meters 3:41/mile or 2:17/km 4:07/mile or 2:34/km
1 mile 3:43/mile or 2:19/km 4:13/mile or 2:37/km
5K 4:04/mile or 2:31/km 4:34/mile or 2:50/km
10K 4:14/mile or 2:38/km 4:45/mile or 2:57/km
Half Marathon
(13.11 miles / 21.098 km) 4:27/mile or 2:46/km 4:58/mile or 3:05/km
Marathon
(26.22 miles / 42.195 km) 4:41/mile or 2:55/km 5:10/mile or 3:13/km
Step-by-step explanation: sorry if this is wromg :/ ( but if it is please add me as the brainist answer )
Answer:
D.7
Step-by-step explanation:
a: Answer is cuboid
b: top & base will be 5*6 = 30 in ^2
both right & left side wil be 5*2 = 10 in^2
front & back will be 6*2 = 12 in^2
Hope that will help you :)
Answer:
0.347% of the total tires will be rejected as underweight.
Step-by-step explanation:
For a standard normal distribution, (with mean 0 and standard deviation 1), the lower and upper quartiles are located at -0.67448 and +0.67448 respectively. Thus the interquartile range (IQR) is 1.34896.
And the manager decides to reject a tire as underweight if it falls more than 1.5 interquartile ranges below the lower quartile of the specified shipment of tires.
1.5 of the Interquartile range = 1.5 × 1.34896 = 2.02344
1.5 of the interquartile range below the lower quartile = (lower quartile) - (1.5 of Interquartile range) = -0.67448 - 2.02344 = -2.69792
The proportion of tires that will fall 1.5 of the interquartile range below the lower quartile = P(x < -2.69792) ≈ P(x < -2.70)
Using data from the normal distribution table
P(x < -2.70) = 0.00347 = 0.347% of the total tires will be rejected as underweight
Hope this Helps!!!
