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IRINA_888 [86]
3 years ago
11

A number n is 13 less than a second number, and the second number is 10 more than a third number. If the third number is 54, wha

t is n?
A) 31
B) 41
C) 51
D) 57
E) 77
Mathematics
2 answers:
MariettaO [177]3 years ago
6 0
N = number
s = second number

n = s - 13
s = 54 + 10

s = 64

Plug in 64 for s

n = (64) - 13
n = 51

C) 51 is your answer

hope this helps
Ivanshal [37]3 years ago
5 0
51, in explainatory terms, you would want to add ten to fifty-four then subtract 13
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A= l x w
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10x^3 - 20x^2 + 65x
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The function f is defined by f(x) = x + 3 / 4x - 5 . Find f(x+3).​
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x+6 / 4x-5

Step-by-step explanation:

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3 years ago
How do you solve his with working
AlexFokin [52]
Check the picture below.

a)

so the perimeter will include "part" of the circumference of the green circle, and it will include "part" of the red encircled section, plus the endpoints where the pathway ends.

the endpoints, are just 2 meters long, as you can see 2+15+2 is 19, or the radius of the "outer radius".

let's find the circumference of the green circle, and then subtract the arc of that sector that's not part of the perimeter.

and then let's get the circumference of the red encircled section, and also subtract the arc of that sector, and then we add the endpoints and that's the perimeter.

\bf \begin{array}{cllll}
\textit{circumference of a circle}\\\\ 
2\pi r
\end{array}\qquad \qquad \qquad \qquad 
\begin{array}{cllll}
\textit{arc's length}\\\\
s=\cfrac{\theta r\pi }{180}
\end{array}\\\\
-------------------------------

\bf \stackrel{\stackrel{green~circle}{perimeter}}{2\pi(7.5) }~-~\stackrel{\stackrel{green~circle}{arc}}{\cfrac{(135)(7.5)\pi }{180}}~+
\stackrel{\stackrel{red~section}{perimeter}}{2\pi(9.5) }~-~\stackrel{\stackrel{red~section}{arc}}{\cfrac{(135)(9.5)\pi }{180}}+\stackrel{endpoints}{2+2}
\\\\\\
15\pi -\cfrac{45\pi }{8}+19\pi -\cfrac{57\pi }{8}+4\implies \cfrac{85\pi }{4}+4\quad \approx \quad 70.7588438888



b)

we do about the same here as well, we get the full area of the red encircled area, and then subtract the sector with 135°, and then subtract the sector of the green circle that is 360° - 135°, or 225°, the part that wasn't included in the previous subtraction.


\bf \begin{array}{cllll}
\textit{area of a circle}\\\\ 
\pi r^2
\end{array}\qquad \qquad \qquad \qquad 
\begin{array}{cllll}
\textit{area of a sector of a circle}\\\\
s=\cfrac{\theta r^2\pi }{360}
\end{array}\\\\
-------------------------------

\bf \stackrel{\stackrel{red~section}{area}}{\pi(9.5^2) }~-~\stackrel{\stackrel{red~section}{sector}}{\cfrac{(135)(9.5^2)\pi }{360}}-\stackrel{\stackrel{green~circle}{sector}}{\cfrac{(225)(7.5^2)\pi }{360}}
\\\\\\
90.25\pi -\cfrac{1083\pi }{32}-\cfrac{1125\pi }{32}\implies \cfrac{85\pi }{4}\quad \approx\quad 66.75884

7 0
3 years ago
Olga has 5 times as many dimes as nickels. if she has $3.30, how many of each coin does she have
Colt1911 [192]
She should have 
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dimes: 30 . = 300
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6 0
3 years ago
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Someone pls help me with this and I’ll mark you as brainliest!!
MrRissso [65]

Answer:

2. I am pretty sure that it is right angles are congruent.

4. Angle O and R are congruent, never heard of their angles theorem but I think it might be related to CPCTC.

Step-by-step explanation:

Well a square is always used to represent a right angle so and both angle Q and N have squares and that should mean that they are both 90 degrees. Also while vertical angels are congruent, angles Q and N are not vertical from each other, Reflexive Property is if it is a side and not an angle I think.

5 0
3 years ago
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