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miv72 [106K]
3 years ago
6

Simplify (7x-1)(2x+5)

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
3 0

Answer:

14x² - 37x + 5

Step-by-step explanation:

Use FOIL (First, Outer, Inner, Last):

(7x-1)(2x-5) = 14x^2 -37x+5

That's your answer.

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Which figure shows a reflection of ​pre-image QRS​ over the line t?
Igoryamba

Answer:

A, because its reflecting off of the y axis

Step-by-step explanation:

I have proof links, and I took the test

4 0
3 years ago
Plzzz help i need A.S.A.P
Vladimir79 [104]
Hope this helps you. :)

3 0
3 years ago
Read 2 more answers
7(z+2)-3z=44 quiero que me ayuden a resolver este problema por favor
slega [8]
No hablo expanol

7(z+2)-3z=44
7z+14-3z=44
7z-3z+14=44
4z+14=44
-14        -14
4z+14-14=44-14
4z+0=30
4z=30
1/4  1/4
(4z)/4=30/4
(4/4)z=15/2
1z=15/2
z=15/2



z=15/2
5 0
3 years ago
Perimeter is a measure of distance around a figure. If each side of a triangle measures 0.75 inches, what is the perimeter of th
Alexxx [7]
Perimeter = 0.75 * 3 = 2.25 <span>inches</span>
3 0
3 years ago
A parabola can be drawn given a focus of (-11, -2) and a directrix of x= -3
fgiga [73]

Check the picture below, so the parabola looks more or less like that.

now, the vertex is half-way between the focus point and the directrix, so that puts it where you see it in the picture, and the horizontal parabola is opening to the left-hand-side, meaning that the distance "P" is negative.

\textit{horizontal parabola vertex form with focus point distance} \\\\ 4p(x- h)=(y- k)^2 \qquad \begin{cases} \stackrel{vertex}{(h,k)}\qquad \stackrel{focus~point}{(h+p,k)}\qquad \stackrel{directrix}{x=h-p}\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix}\\\\ \stackrel{"p"~is~negative}{op ens~\supset}\qquad \stackrel{"p"~is~positive}{op ens~\subset} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}

\begin{cases} h=-7\\ k=-2\\ p=-4 \end{cases}\implies 4(-4)[x-(-7)]~~ = ~~[y-(-2)]^2 \\\\\\ -16(x+7)=(y+2)^2\implies x+7=-\cfrac{(y+2)^2}{16}\implies x=-\cfrac{1}{16}(y+2)^2-7

8 0
2 years ago
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