Answer:
2. All the naturally occurring isotopes of Mg.
Explanation:
You want to know the atomic mass of the magnesium you use in the lab. That’s “natural” magnesium. So, you must use the weighted average of all the naturally occurring isotopes in natural Mg.
1. and 3. are <em>wrong</em>. You won’t get the correct mass for natural Mg if you use only the artificial isotopes for your calculation.
4. is <em>wrong</em>. You must use all the naturally occurring isotopes. The two most abundant isotopes of Mg account for only 90 % of the atoms. If you ignore the other 10 %, your calculation will be wrong.
=<span><span><span><span><span><span><span><span><span>148.413159d</span><span>f2</span></span>i</span>l</span><span>o4</span></span>s</span>y</span>+<span><span>a<span>l2</span></span><span>o3</span></span></span>+<span>a<span>l is the answer and have a nice day :)</span></span></span>
Answer:
CaCO3
Explanation:
The molecule is formed by the calcium cation Ca+2 and the carbonate anion CO3−2.
