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3 years ago

True or false, The mass of an electron is equal to the mass of a neutron.

Chemistry

1 answer:

Rufina [12.5K]3 years ago

5 0

Answer:

False

Explanation:

No, the mass of an electron is not equal to the mass of a neutron. Mass of neutron is greater than the mass of an electron.

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Which of these mixtures will MOST LIKELY result in soil? A) sand, clay, and heat B) sand, clay, and water C) sand, clay, heat, a

Wewaii [24]

Answer:

I think it should be C.

Explanation:

Because for a plant to start photosinthesis it need sun (heat is like the sun),water,and stuff that soil is made of (sand and clay) tell me if this is correct

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4 years ago

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What happens in this circuit if one of the light bulbs burns out?

bulgar [2K]

4.The other light bulb will stay on and glow brightly.

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3 years ago

The element silver exists in nature as two isotopes: 107Ag has a mass of 106.9051 u, and 109Ag has a mass of 108.9048 u. The ave

Lilit [14]

Answer:

107Ag has abundance of 51.7%

109Ag has abundance of 48.3%

Explanation: Please see attachment for explanation

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3 years ago

For any molecule at the surface the resulting surrounding forces equal zero

Katarina [22]

False is the correct answer

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3 years ago

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The combustion of 0.570 g of benzoic acid (ΔHcomb = 3,228 kJ/mol; MW = 122.12 g/mol) in a bomb calorimeter increased the tempera

torisob [31]

Answer:

The temperature change from the combustion of the glucose is 6.097°C.

Explanation:

Benzoic acid;

Enthaply of combustion of benzoic acid = 3,228 kJ/mol

Mass of benzoic acid = 0.570 g

Moles of benzoic acid = $\frac{0.570 g}{122.12 g/mol}=0.004667 mol$

Energy released by 0.004667 moles of benzoic acid on combustion:

$Q=3,228 kJ/mol \times 0.004667 mol=15.0668 kJ=15,066.8 J$

Heat capacity of the calorimeter = C

Change in temperature of the calorimeter = ΔT = 2.053°C

$Q=C\times \Delta T$

$15,066.8 J=C\times 2.053^oC$

$C=7,338.92 J/^oC$

Glucose:

Enthaply of combustion of glucose= 2,780 kJ/mol.

Mass of glucose=2.900 g

Moles of glucose = $\frac{2.900 g}{180.16 g/mol}=0.016097 mol$

Energy released by the 0.016097 moles of calorimeter combustion:

$Q'=2,780 kJ/mol \times 0.016097 mol=44.7491 kJ=44,749.1 J$

Heat capacity of the calorimeter = C (calculated above)

Change in temperature of the calorimeter on combustion of glucose = ΔT'

$Q'=C\times \Delta T'$

$44,749.1 J=7,338.92 J/^oC\times \Delta T'$

$\Delta T'=6.097^oC$

The temperature change from the combustion of the glucose is 6.097°C.

6 0

3 years ago