Answer:
Covalent bond
Explanation:
Covalent bond:
"The bond which is formed by the sharing of electrons between the atoms is called covalent bond"
The covalent bond is less stronger than ionic bond so require less energy to break as compared to the energy require to break the ionic bond.
The covalent bond is present between the oxygen molecule. It is the bond which is formed by the sharing of electrons between the two atoms of oxygen. Oxygen is present in group six of periodic table so there are six valance electrons are present. Oxygen molecules is formed by sharing the two valance electrons by each oxygen atom, thus double covalent bond is present in oxygen molecules. This is represented as O=O and two lone pairs are still present on each oxygen atom.
Answer:
Carbohydrates
Explanation:
Increased exercise intensity means the overall need for energy increases. As we increase exercise intensity we increase our glucose uptake and oxidation which far exceeds uptake, indicating that muscle stores of glycogen are being used. At moderate intensities (65%) there is an increased need for muscle glycogen and muscle triglycerides which is fat. At higher levels of intensities (85%) there is an even greater need for energy, and this is met almost solely by an increased uptake of glucose from the blood and from muscle glycogen.
In the case of fats as an energy fuel source at high intensities, increasing levels of intensity increases fat oxidation but once we get into higher levels of intensity, we return to levels of fat oxidation similar to very low intensities.
Formula for the depression in freezing point is:
-(1)
where
is depression in freezing point,
is Van't Hoff factor,
is molal freezing point depression constant, and
is molality of the solution.
Molality of the solution,
(given)
Molal freezing point depression constant of water, ![k_f = 1.86^{o}C/m](https://tex.z-dn.net/?f=k_f%20%3D%201.86%5E%7Bo%7DC%2Fm)
Depression in freezing point of solution, ![\Delta T_f = T_{water solvent} - T_{solution}](https://tex.z-dn.net/?f=%5CDelta%20T_f%20%3D%20T_%7Bwater%20solvent%7D%20-%20T_%7Bsolution%7D)
![\Delta T_f = {0^{o}C} - ({-2.6^{o}C}) = 2.6^{o}C](https://tex.z-dn.net/?f=%5CDelta%20T_f%20%3D%20%7B0%5E%7Bo%7DC%7D%20-%20%28%7B-2.6%5E%7Bo%7DC%7D%29%20%3D%202.6%5E%7Bo%7DC)
Substituting the values in equation (1):
![\2.6^{o}C = i\times 1.86^{o}C/m\times 0.99 m](https://tex.z-dn.net/?f=%5C2.6%5E%7Bo%7DC%20%3D%20i%5Ctimes%201.86%5E%7Bo%7DC%2Fm%5Ctimes%200.99%20m)
![i = \frac{2.6^{o}C}{1.86^{o}C/m\times 0.99 m} = 1.412](https://tex.z-dn.net/?f=i%20%3D%20%5Cfrac%7B2.6%5E%7Bo%7DC%7D%7B1.86%5E%7Bo%7DC%2Fm%5Ctimes%200.99%20m%7D%20%3D%201.412)
Hence, the Van't Hoff factor (i) for
is 1.412.
Answer:
The amount of energy transferred to the diamond while being cut is thus Q = 852000 J
Explanation:
Since quantity of heat transferred Q = mcΔθ where m = mass of substance , c = specific heat capacity of substance and Δθ = temperature change.
Now, given that for diamond, m = mass of diamond = 600 g, c = specific heat capacity of diamond = 710 J/g°C and Δθ = temperature change = 2 °C.
So, the amount of energy transferred to the diamond while being cut is thus
Q = mcΔθ
Q = 600 g × 710 J/g°C × 2 °C
Q = 852000 J
So, the amount of energy transferred to the diamond while being cut is thus Q = 852000 J
Metallic bond
Metals are bound together by metallic bonds characterized by the sharing of free electrons among a lattice of the metal ions. This type of bonding gives metals unique properties such as strength, ductility, malleability, electrical and thermal conductivity, opacity, and luster.
This property of metal to be flattened and shaped is called malleability. When stress is applied to the metal, its atoms merely roll or slide over each other into new positions while keeping the metallic bond intact. The bonds do not break, thereby allowing the metal to be flattened out instead of crumbling or breaking into pieces.