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padilas [110]
3 years ago
13

Why do some scientists prefer to express concentrations of water contaminants in the units ppm and ppb rather than molarity?

Chemistry
1 answer:
ira [324]3 years ago
4 0

Explanation:

These molarity units are used to express very small solute concentrations. Molarity cannot be used to express small amount of solute dissolved in solvents.

parts per million ppm  is a dimensionless quantity that represents the part of a whole number in units of \frac{1}{1000000}

parts per billion ppb represents the part of a whole in units of  \frac{1}{1000000000}

These quantities are useful in determining very small amount of solute like gold concentration in stream sediments.

Learn more:

ppm brainly.com/question/2854033

#learnwithBrainly

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How would Earths revolution be affected if it had a larger orbit??
Sidana [21]

Answer:

When the Earth rotates on its axis, it prevents air currents from going in a straight line to the north and the south from the equator. It results in one of the effects of rotation of the Earth: the Coriolis Effect.

4 0
2 years ago
15 POINTS PLEASE HELP What volume of water must be added to 35mL of 2.6m KCl to reduce its concentration to 1.2m? Please explain
BartSMP [9]
First, find the volume the solution needs to be diluted to in order to have the desired molarity:
You have to use the equation M₁V₁=M₂V₂ when ever dealing with dilutions.

M₁=the starting concentration of the solution (in this case 2.6M)
V₁=the starting volume of the solution (in this case 0.035L)
M₂=the concentration we want to dilute to (in this case 1.2M)
V₂=the volume of solution needed for the dilution (not given)

Explaining the reasoning behind the above equation:
MV=moles of solute (in this case KCl) because molarity is the moles of solute per Liter of solution so by multiplying the molarity by the volume you are left with the moles of solute.  The moles of solute is a constant since by adding solvent (in this case water) the amount of solute does not change.  That means that M₁V₁=moles of solute=M₂V₂ and that relationship will always be true in any dilution.

Solving for the above equation:
V₂=M₁V₁/M₂
V₂=(2.6M×0.035L)/1.2M
V₂=0.0758 L
That means that the solution needs to be diluted to 75.8mL to have a final concentration of 1.2M.

 Second, Finding the amount of water needed to be added:
Since we know that the volume of the solution was originally 35mL and needed to be diluted to 75.8mL to reach the desired molarity, to find the amount of solvent needed to be added all you do is V₂-V₁ since the difference in the starting volume and final volume is equal to the volume of solvent added.
75.8mL-35mL=40.8mL
40.8mL of water needs to be added

I hope this helps.  Let me know if anything is unclear.
Good luck on your quiz!
5 0
3 years ago
What is the oxidation state of each element in the species Mn(ClO4)3?
gayaneshka [121]
The oxidation state of the compound Mn (ClO4)3 is to be determined in this problem. For oxygen, the charge is 2-, the total considering its number of atoms is -24. Mn has a charge of +3. TO compute for Mn, we must achieve zero charge overall hence 3+3x-24=0 where x is the Cl charge. Cl charge, x is +7. 
7 0
3 years ago
Read 2 more answers
Which structures join with the cell’s membrane during exocytosis?
erma4kov [3.2K]

Answer:Exocytosis is also used to integrate new proteins into the cell membrane. In this process, the new protein is formed inside the cell, and migrates to phospholipid bilayer of the vesicle. The vesicle, containing the new protein as a part of the phospholipid bilayer, fuses with the cell membrane.

Explanation:

8 0
3 years ago
He following balanced equation shows the formation of water. 2H2 + O2 mc020-1.jpg 2H2O How many moles of oxygen (O2) are require
mrs_skeptik [129]

Answer : The correct option is, 13.7 mole

Solution : Given,

Moles of H_2 = 27.4 moles

The given balanced chemical reaction is,

2H_2+O_2\rightarrow 2H_2O

From the balanced chemical reaction, we conclude that

As, 2 moles of H_2 react with 1 moles of O_2

So, 27.4 moles of H_2 react with \frac{27.4}{2}=13.7 moles of O_2

Therefore, the number of moles of oxygen O_2 required are, 13.7 moles

7 0
3 years ago
Read 2 more answers
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