Write 3.6*10 to the eleventh power in calulator notation
1 answer:
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Answer:
Options (1), (2), (4) and (5) are correct.
Step-by-step explanation:
Characteristics of the given hyperbola,
1). Vertex of the given hyperbola are at (-3, 6) and (-3, 4).
2). Since center of a hyperbola is the center of a line joining vertices of the hyperbola,
Center of the given parabola will be,
⇒ (-3, 5)
3). Vertical line joining the foci of the hyperbola is the transverse axis.
4). A line perpendicular to the transverse axis and passing through the center will be the conjugate axis.
5). Directrices of a horizontal hyperbola are the horizontal lines.
Therefore, Options (1), (2), (4) and (5) are correct.