Answer:
The dimensions of the rectangular volleyball court are 60 ft x 30 ft
Step-by-step explanation:
Let
x ----> the length of rectangular volleyball court
y ---> the width of the rectangular volleyball court
we know that
The area of the rectangular volleyball court is equal to


so
----> equation A
-----> equation B
substitute equation B in equation A


Solve for y
Simplify

take square root both sides

<em>Find the value of x</em>

substitute the value of y

therefore
The dimensions of the rectangular volleyball court are 60 ft x 30 ft
You need to work backwards
if it is no more than 9 units away from 8
thus x must be 8-9<x<8+9 solving -1<x<17
so the answer is 4.
Answer:
12 and 8
Step-by-step explanation:
set two numbers as x and y
mean of 10 → x+y/2=10
range of 4 → x-y=4
x+y=20
+ x-y=4
____________
2x=24, x=12
12-y=4, y=8
Basically you just need to multiply the two fractions together to get the depth of the turtle. Therefore the turtle is 3/12 miles deep or 1/4 mile deep.