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3 years ago

Erin's family has completed 70% of a trip. They have traveled 35 miles. How far is the trip?

Mathematics

1 answer:

Alexxandr [17]3 years ago

7 0

Answer:

Their trip is 50 mile long.

Step-by-step explanation:

I first divided 70 by 35 to get two.The two represents 1 mile = 2%. So then I subtracted 70 from 100 to get 30 then I divided 30 by 2 to get 15. Then I added 15 to the original 35 to get 50 miles for their 100%/destination of their trip. Hope this helps! Have a great day!

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Answer:

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3 years ago

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3 years ago

Solve 42 div 3 using an area model

ololo11 [35]

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3 years ago

A scientist has a container of 2% acid solution and a container of 5% acid solution. How many fluid ounces of each concentration

algol [13]

Let 'a' be the number of ounces of 2%-solution in the 25-ounce mixture

and 'b' be the number of ounces of 5%-solution in the 25-ounce mixture.

Since, fluid ounces of each concentration should be combined to make 25 fl oz.

So, a+b=25 (Equation 1)

And, a container of 2% acid solution and a container of 5% acid solution should be combined to make 25 fl oz of 3.2% acid solution.

So, a of 2% + b of 5% = 3.2% of 25

$(a \times \frac{2}{100})+(b \times \frac{5}{100})= 25 \times \frac{3.2}{100}$

$(0.02a)+(0.05b)= 0.8$

Multiplying the above equation by 100, we get

$2a+5b=80$ (Equation 2)

Substituting the value of a=25-b in equation 2, we get

$2(25-b)+5b=80$

$50-2b+5b=80$

$50+3b=80$

$3b=30$

$b=10$

Since, a=25-b

a= 25-10

a=15.

So, 15 fluid ounces of 2% solution combined with 10 ounces of the 5% solution to create a 25-ounce mixture at 3.2% concentration of acid.

7 0

3 years ago

Area triangles? it says show work so pls do

coldgirl [10]

$\large{\underline{\underline{\pmb{\sf {\color {blue}{Solution:}}}}}}$

Given,

Area = 225 yd²

Base = 30 yd

Height = [To be calculated]

To find:

The height of the given triangle.

We know that, area of a triangle is:

$\frac{1}{2} \times (b \times h) \\ \\ \leadsto \frac{1}{2} \times (30 \times h) \\ \\ \leadsto \frac{1}{2} \times 30h \\ \\ \leadsto \frac{1}{ \cancel{2}} \times \cancel{30}h \\ \\ \leadsto1 \times 15h \\ \\ \leadsto \: h = 15 \: yd$

Therefore, the require height is 15 yd.

$\green\star$ Proof:

$\frac{1}{2} \times (b \times h) \\ \\ \leadsto \frac{1}{2} \times (30 \times 15) \\ \\ \leadsto \frac{1}{ \cancel{2}} \times \cancel{450} \\ \\ \leadsto1 \times 225 \\ \\ area = 225 {yd}^{2}$

$\boxed{ \frak \red{brainlysamurai}}$

6 0

1 year ago