Explanation:
To find the number of atoms in each specie, we consider the coefficient and the subscript of each of the given atoms.
1. NaCl:
Na = 1 atom
Cl = 1 atom
2. CO₂
C = 1 atom
O = 2 atom
3. O₂
O = 2 atoms
4. C₆H₁₂O₆
C = 6 atoms
H = 12 atoms
O = 6 atoms
For the second part;
1. 2NaCl
Na = 2 atoms
Cl = 2 atoms
2. 3CO₂
C = 3 atoms
O = 6 atoms
3. 4O₂
O = 8 atoms
4. 2C₆H₁₂O₆
C = 12 atoms
H = 24 atoms
O = 12 atoms
Answer: see explanation
Explanation:
A. substrate
B. Active site
C. Enzyme binds with substrate
D. Active site of enzyme
E. Products leaving active site
Simplified enzymatic reaction. The substrate reversibly binds to the active site of the enzyme, forming the enzyme-substrate (ES) complex. The bound substrate is converted to product by catalytic groups in the active site, forming the enzyme-product complex (EP). The bound products are released, returning the enzyme to its unbound form, ready to catalyze another round of converting substrate to product.
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