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inessss [21]
3 years ago
5

How does Gregor Mendel's work demonstrate support for the concepts of dominant and recessive alleles?

Biology
1 answer:
taurus [48]3 years ago
6 0
<span>From the proportions of phenotypes in the offspring. If Genes would be equal you would get 1/4 A, 1/4 B and 1/2 AB; but you often get 1/4 A and 3/4 B. </span>I hope that this is the answer that you were looking for and it has helped you.
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What inferences can you make regarding the ph of a particular part of the digestive system and the type and relative size of the
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Read 2 more answers
a researcher wishes to know whether there is a significant difference in the number of knee injuries reported among four sports.
boyakko [2]

Answer:

Chi-square analysis cannot be used to check for significant difference in the number of knee injuries among four sports.

Explanation:

The chi-square analysis is a statistical procedure that is used to test association between measured variables or goodness of fits of a set of measured variables to expected outcomes.

<em>In the case of testing for significant difference, chi-square analysis cannot be used as testing for significant difference in two or more means requires using t-test, analysis of variance, or any other relevant statistical procedure.</em>

To compare number of knee injuries reported among four sports for significant difference, the most suitable statistical procedure would be analysis of variance.

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8 0
3 years ago
In a unique species of plants, flowers may be yellow, blue, red, or mauve. All colors may be true-breeding. If plants with blue
Zolol [24]

Answer:

F1) 100% bbRr, red flowered plants.

Explanation:

<u>Available data:</u>

  • flowers may be yellow, blue, red, or mauve
  • colors may be true-breeding
  • the cross of blue-flowered plants with red-flowered plants, produce plants that have yellow flowers
  • F2 generation: 9/16 yellow, 3/16 blue, 3/16 red, and 1/16 mauve.

Knowing that the phenotypic ratio is 9:3:3:1, we can assume that there are two genes involved in the flower color expression. We can name these genes B and R with a dominant and a recessive allele each (B, b and R, r respectively).

According to the first cross, we might establish the following genotypes:

1st Cross: blue-flowered plant     x     red-flowered plant

Parentals)         BBrr                     x                bbRR

Gametes)     Br, Br, Br, Br                         bR, bR, bR, bR

F1) 100% BbRr, yellow plants

Parentals)   BbRr     x     BbRr

Gametes) BR, Br, bR, br

                BR, Br, bR, br

Punnett square)     BR       Br        bR          br

                  BR     BBRR    BBRr   BbRR     BbRr

                  Br      BBRr     BBrr     BbRr      Bbrr

                  bR     BbRR    BbRr    bbRR      bbRr                    

                  br      BbRr     Bbrr      bbRr      bbrr

F2)  9/16 yellow ---> 1/16 BBRR + 2/16 BBRr + 4/16 BbRr + 2/16 BbRR  

       3/16 blue ------> 1/16 BBrr + 2/16 Bbrr

       3/16 red---------> 1/16 bbRR + 2/16 bbRr

       1/16 mauve ----> 1/16 bbrr    

So,

  • Yellow-flowered plants: BBRR, BBRr, BbRR, BbRr
  • Red-flowered plants: bbRR, bbRr
  • Blue-flowered plants: BBrr, Bbrr
  • Mauve-flowered plants: bbrr

According to these genotypes, the second cross would be like following,

2nd Cross: true-breeding red-flowered plants with true-breeding mauve flowered plants.                

Parentals)          bbRR       x        bbrr

Phenotype)       Red                   Mauve

Gametes)   bR, bR, bR, bR      br, br, br, br

Punnett square)    bR       bR        bR        bR                    

                    br    bbRr     bbRr    bbRr     bbRr

                    br    bbRr     bbRr    bbRr     bbRr

                    br    bbRr     bbRr    bbRr     bbRr

                    br    bbRr     bbRr    bbRr     bbRr

F1) 100% bbRr, red flowered plants.

6 0
3 years ago
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