Answer:
The number of passcodes possible is 1,100,000
Step-by-step explanation:
Here , we want to calculate the number of different possible passcodes.
For the five digit code,
each number in the code has a possibility of choosing from the digits 0 to 9, so this means that each of the numbers in the code has 10 options.
So for a five digit code, the number of possible choices would be 10 * 10 * 10 * 10 * 10 = 10^5
For a six digit code, the number of possible choice would be 10 * 10 * 10 * 10 * 10 * 10 * 10 = 10^6
So for 5 or 6 digits code, the number of possible choices would be;
10^5 + 10^6 = 10^5(1 + 10)
= 11(10^5) = 1,100,000
1.) the answer would be D
2.) D
C=20+0.07(100)
C=20+7
C=27
3.) B
4y-10=22
+10 +10
4y=32
/4 /4
Y=8
4.)$132
60r+0.06(50r)=p
60(4)+0.06(50*4)=p
120+12=p
132=p
5.) $9.40
7+0.012(10,000-8,000)
7+0.0012(2,000)
7+2.4
9.4
Answer:
The answer is "".
Step-by-step explanation:
In the given question the y-coordinates range between -1 to -2. Its distance between -1 and -2 is near, and less than halfway.
B=cost per boquet
v=cost per vase
3b+5v=25.75
8b+2v=29.00
use eliminateion
divide 2nd equation by 2
4b+v=14.50
multiply it by -5 and add to other equation to eliminate v
-20b-5v=-72.5
<span><u>3b+5v=25.75 +</u></span><u />
-17b+0v=-46.75
-17b=-46.75
divide both sides by -17
b=2.75
a boquet costs $2.75
Answer:
Perimeter is 72 mm
Step-by-step explanation:
Regular Hexagon - 6 equal sides
12 x 6= 72
So, perimeter is 72mm
Hope this helps!