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Gelneren [198K]
3 years ago
5

Classify the number (choose all that apply): -20 *

Mathematics
1 answer:
Citrus2011 [14]3 years ago
6 0

Answer:

Whole Number

Integer x

Rational Number

Irrational Number x

Step-by-step explanation:

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Which of the following properties is this? <br><br> 8x/3 • 3/8x = 1
kolezko [41]

Answer:

Multiplication

Step-by-step explanation:

Multiplication

7 0
3 years ago
Subtract 4/9 and 1/5 in the simplest form
Reptile [31]

Answer:

4/9 or 0.4

Step-by-step explanation:

7 0
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Helppppppppppppppppppppppppppp
GaryK [48]
Answer:
cot θ = √15 / 7

Explanation:
csc θ = 1 / sin θ
In a right angled triangle, sin θ = opposite / hypotenuse
This means that:
csc θ = hypotenuse / opposite = 8 / 7
So, we have:
opposite = 7 units and hypotenuse = 8 units
We will use the Pythagorean theorem to get the adjacent side as follows:
(hypotenuse)^2 = (opposite)^2 + (adjacent)^2
(8)^2 = (7)^2 + (adjacent)^2
(adjacent)^2 = 15
adjacent =  √15 units

Now, we want to get the value of cot θ.
We know that:
cot θ = 1 / tan θ
Since tan θ = opposite / adjacent
Therefore:
cot θ = adjacent / opposite = √15 / 7

Hope this helps :)
4 0
3 years ago
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Cory is a bird watcher he estimates that 30% of the birds he sees are american robins, 20% are dark eyed juncos and 20% are slnc
dezoksy [38]

Answer:

I think C. 0.75

Step-by-step explanation:

8 0
3 years ago
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Intersection point of Y=logx and y=1/2log(x+1)
GalinKa [24]

Answer:

The intersection is (\frac{1+\sqrt{5}}{2},\log(\frac{1+\sqrt{5}}{2}).

The Problem:

What is the intersection point of y=\log(x) and y=\frac{1}{2}\log(x+1)?

Step-by-step explanation:

To find the intersection of y=\log(x) and y=\frac{1}{2}\log(x+1), we will need to find when they have a common point; when their x and y are the same.

Let's start with setting the y's equal to find those x's for which the y's are the same.

\log(x)=\frac{1}{2}\log(x+1)

By power rule:

\log(x)=\log((x+1)^\frac{1}{2})

Since \log(u)=\log(v) implies u=v:

x=(x+1)^\frac{1}{2}

Squaring both sides to get rid of the fraction exponent:

x^2=x+1

This is a quadratic equation.

Subtract (x+1) on both sides:

x^2-(x+1)=0

x^2-x-1=0

Comparing this to ax^2+bx+c=0 we see the following:

a=1

b=-1

c=-1

Let's plug them into the quadratic formula:

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

x=\frac{1 \pm \sqrt{(-1)^2-4(1)(-1)}}{2(1)}

x=\frac{1 \pm \sqrt{1+4}}{2}

x=\frac{1 \pm \sqrt{5}}{2}

So we have the solutions to the quadratic equation are:

x=\frac{1+\sqrt{5}}{2} or x=\frac{1-\sqrt{5}}{2}.

The second solution definitely gives at least one of the logarithm equation problems.

Example: \log(x) has problems when x \le 0 and so the second solution is a problem.

So the x where the equations intersect is at x=\frac{1+\sqrt{5}}{2}.

Let's find the y-coordinate.

You may use either equation.

I choose y=\log(x).

y=\log(\frac{1+\sqrt{5}}{2})

The intersection is (\frac{1+\sqrt{5}}{2},\log(\frac{1+\sqrt{5}}{2}).

6 0
3 years ago
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