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77julia77 [94]
3 years ago
13

Put <, >, or = for 2-9

Mathematics
1 answer:
myrzilka [38]3 years ago
5 0

2. =

3. >

4. =

5. >

6. >

7. <

8. >

9. =

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1000x8129= WILL MAKR BRANLYEST
8_murik_8 [283]

Answer:

it is 8,129,000

Step-by-step explanation:

1000x8129 = 8,129,000

8 0
2 years ago
A newborn baby weighs 8 pounds and decreases his weight by 5% every week how much does the baby weigh after 20 weeks?
Feliz [49]

Answer:

in 20 weeks the baby will weigh nothing and is definitely dead

Step-by-step explanation:

5% of 8 is . 4

.4 x 20 is 8

5 0
2 years ago
Read 2 more answers
A marketing firm would like to test-market the name of a new energy drink targeted at 18- to 29-year-olds via social media. A st
Anon25 [30]

Answer:

(a) The probability that a randomly selected U.S. adult uses social media is 0.35.

(b) The probability that a randomly selected U.S. adult is aged 18–29 is 0.22.

(c) The probability that a randomly selected U.S. adult is 18–29 and a user of social media is 0.198.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = an US adult who does not uses social media.

<em>Y</em> = an US adult between the ages 18 and 29.

<em>Z</em> = an US adult between the ages 30 and above.

The information provided is:

P (X) = 0.35

P (Z) = 0.78

P (Y ∪ X') = 0.672

(a)

Compute the probability that a randomly selected U.S. adult uses social media as follows:

P (US adult uses social media (<em>X'</em><em>)</em>) = 1 - P (US adult so not use social media)

                                                   =1-P(X)\\=1-0.35\\=0.65

Thus, the probability that a randomly selected U.S. adult uses social media is 0.35.

(b)

Compute the probability that a randomly selected U.S. adult is aged 18–29 as follows:

P (Adults between 18 - 29 (<em>Y</em>)) = 1 - P (Adults 30 or above)

                                            =1-P(Z)\\=1-0.78\\=0.22

Thus, the probability that a randomly selected U.S. adult is aged 18–29 is 0.22.

(c)

Compute the probability that a randomly selected U.S. adult is 18–29 and a user of social media as follows:

P (Y ∩ X') = P (Y) + P (X') - P (Y ∪ X')

                =0.22+0.65-0.672\\=0.198

Thus, the probability that a randomly selected U.S. adult is 18–29 and a user of social media is 0.198.

6 0
2 years ago
Jonas wants to mail a package that weighs 4.2 kilogram. how much dose the package weigh in pounds?
mash [69]

jonas wants to mail a package that weighs 4.2 kilogram. how much dose the package weigh in pounds?​

we know that

1 kg = 2.20462262185 lb

1 kg=2.2 lb

we have

4.2 kg

Convert to pounds

so

4.2 kg=4.2*(2.2)=9.24 pounds

therefore

the answer is 9.24 pounds

7 0
10 months ago
50,000 x (2 + 5/100)<br> 50,000 x (3 + 5/100)<br> 50,000 x (4 + 5/100)<br> 50,000 x (5 + 5/100)
ELEN [110]

Answer:

Solution for What is 5 percent of 50000:

5 percent *50000 =

( 5:100)*50000 =

( 5*50000):100 =

250000:100 = 2500

Step-by-step explanation:

7 0
3 years ago
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