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Dvinal [7]
3 years ago
14

Find the future value of $2,000 deposited into a retirement account, after 20 years, if the interest rate is 6%, compounded quar

terly. (Use the formula for this problem) $_____
Mathematics
1 answer:
natta225 [31]3 years ago
5 0

Answer:

$ 6581.33 ( approx )

Step-by-step explanation:

Since, future value formula in compound interest is,

A=P(1+\frac{r}{n})^{nt}

Where,

P = Principal amount,

r = annual rate,

n = number of compounding periods in a year,

t = number of years,

Here, P = $ 2,000, r = 6% = 0.06, n = 4 ( 1 year = 4 quarters ),

t = 20 years,

Hence, the future value would be,

A=2000(1+\frac{0.06}{4})^{80}

=2000(1+0.015)^{80}

=2000(1.015)^{80}

=\$ 6581.32557398

\approx \$ 6581.33

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For a binomial distribution with p = 0.20 and n = 100, what is the probability of obtaining a score less than or equal to x = 12
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The binomial distribution is given by, 
P(X=x) =  (^{n}C_{x})p^{x} q^{n-x}
q = probability of failure = 1-0.2 = 0.8
n = 100
They have asked to find the probability <span>of obtaining a score less than or equal to 12.
</span>∴ P(X≤12) = (^{100}C_{x})(0.2)^{x} (0.8)^{100-x}
                    where, x = 0,1,2,3,4,5,6,7,8,9,10,11,12                  
∴ P(X≤12) = (^{100}C_{0})(0.2)^{0} (0.8)^{100-0} + (^{100}C_{1})(0.2)^{1} (0.8)^{100-1} + (^{100}C_{2})(0.2)^{2} (0.8)^{100-2} + (^{100}C_{3})(0.2)^{3} (0.8)^{100-3} + (^{100}C_{4})(0.2)^{4} (0.8)^{100-4} + (^{100}C_{5})(0.2)^{5} (0.8)^{100-5} + (^{100}C_{6})(0.2)^{6} (0.8)^{100-6} + (^{100}C_{7})(0.2)^{7} (0.8)^{100-7} + (^{100}C_{8})(0.2)^{8} (0.8)^{100-8} + (^{100}C_{9})(0.2)^{9} (0.8)^{100-9} + (^{100}C_{10})(0.2)^{10} (0.8)^{100-10} + (^{100}C_{11})(0.2)^{11} (0.8)^{100-11} + (^{100}C_{12})(0.2)^{12} (0.8)^{100-12}


Evaluating each term and adding them you will get,
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