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3 years ago

Pls solve this you get 30 points

Mathematics

1 answer:

babunello [35]3 years ago

6 0

Answer:

$8.25

Step-by-step explanation:

All together for just bowling would be$7.50.

Half off of that is $3.75.

Then all you do is add up everything she used.

3.75 + 2.75 + 1.75 = 8.25

The total before tax is $8.25

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Write a real world problem that compares 0.4 and 0.29. Then solve the problem.

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Lizzy's new neckalce cost 0.4 cents less than lucy's neckalce that cost 0.29. cents.How many cents did lizzy's neckalce cost.

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today, price of a new cell phone is $129. in 2000, the price of a similar cell phone was $240. what is the percent of change in

Ludmilka [50]

To figure this out, you put how much money you changed from then to now as your numerator. So you would have -111 over your original price, which is 240. now, all you have to do is do negative 111÷240 which should be 0.4625. then, to find your percent, all you have to do is move your decimal over to places to the right. 46% decrease!

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3 years ago

Can somebody plz help me [-5+(-7)]^2-(7+3)^2

Firdavs [7]

Answer:

$\boxed{44}$

Step-by-step explanation:

$[-5+(-7)]^2-(7+3)^2$

Resolving Parenthesis

$(-5-7)^2-(10)^2\\(-12)^2-100\\144-100$

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3 years ago

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Help

Art [367]

$\huge\fbox{Answer ☘}$

$\bold{3( \frac{27}{8} ) {}^{ \frac{2}{3} \times - 1} = 2( \frac{32}{243} ) {}^{2x} }\\ \\3(( \frac{3}{2} ) {}^{3} ) {}^{ \frac{2}{3} \times - 1 } = 2(( \frac{2}{3} ) {}^{5} ) {}^{2x} \\\\ 3( \frac{3}{2} ) {}^{2 \times - 1} = 2( \frac{2}{3} ) {}^{10x} \\\\ 3( \frac{2}{3} ) {}^{2} = 2( \frac{2}{3} ) {}^{10x} \\\\ 3( \frac{4}{9} ) = 2( \frac{4}{9} ) {}^{5x} \\\\\bold\pink{ comparing \: powers }\\\\5x = 1 \\\\ \bold\blue{x = \frac{1}{5} }$

hope helpful~

5 0

2 years ago

Need help Asap thank you in advance

julia-pushkina [17]

Answer:

$12x^4-20x^2+32x=4x(3x^3-5x+8)$

Step-by-step explanation:

<u>Common Factors</u>

An algebraic expression that is formed by sums or subtractions of terms can be factored provided there are numeric or variable common factors in all the terms.

The following expression

$Z=12x^4-20x^2+32x$

Can be factored in the constants and in the variable x.

1. To find the common factor of the variable, we must locate if the variable is present in all terms. If so, we take the common factor as the variable with an exponent which is the lowest of all the exponents found throughout the different terms. In this case, the lowest exponent is x (exponent 1).

2. To find the common factors of the constants, we take all the coefficients:

12 - 20 - 32

and find the greatest common divisor of them, i.e. the greatest number all the given numbers can be divided by. This number is 4, since 12/4=3, 20/4=5 and 32/4=8

3. The factored expression is

$Z=12x^4-20x^2+32x=4x(3x^3-5x+8)$

$\boxed{12x^4-20x^2+32x=4x(3x^3-5x+8)}$

3 0

3 years ago