8h/3+19
Move all terms to the left
8-(h/3+19)=0
Get rid of parentheses
-h/3-19+8=0
Multiply all terms by denominator
-h-19*3+8*3=0
Add all numbers and variables together
-1h-33=0
Move all terms containing h to the left all other terms to the right
-h=33
h=33/-1
h=-33
= 4i (2i) <span>√6
= 8i^2 </span><span>√6 but i^2 = -1
= - 8</span><span>√6</span><span>
</span>
Answer:
The relative frequency is found by dividing the class frequencies by the total number of observations
Step-by-step explanation:
Relative frequency measures how often a value appears relative to the sum of the total values.
An example of how relative frequency is calculated
Here are the scores and frequency of students in a maths test
Scores (classes) Frequency Relative frequency
0 - 20 10 10 / 50 = 0.2
21 - 40 15 15 / 50 = 0.3
41 - 60 10 10 / 50 = 0.2
61 - 80 5 5 / 50 = 0.1
81 - 100 <u> 10</u> 10 / 50 = <u>0.2</u>
50 1
From the above example, it can be seen that :
- two or more classes can have the same relative frequency
- The relative frequency is found by dividing the class frequencies by the total number of observations.
- The sum of the relative frequencies must be equal to one
- The sum of the frequencies and not the relative frequencies is equal to the number of observations.
Answer:
B
Step-by-step explanation:
Since the slope is going down the slope is negative and since 50 is positive when 0 its positive.
Also to find slope you do y/x
25/100=1/4 and since its a decreasing pattern the slope is -1/4