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damaskus [11]
3 years ago
9

Pls help me it's due today​

Mathematics
1 answer:
Dimas [21]3 years ago
8 0

Answer:

r³ + 15r² - 10r - 4

Step-by-step explanation:

First, note you can remove the brackets, in this case they contribute nothing at all.

Then, group the like terms and add them, e.g., we have 3r³ and -2r², they add up to r³.

Finally, order them from greatest power of r to smallest power of r.

That's all!

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860÷43 what is the answer?​
Dvinal [7]

Answer:

20

Step-by-step explanation:

You would do this by dividing 43 into 860

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3 years ago
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A farmer wants to build a rectangular garden 10ft long and 6ft wide. How many feet of fencing should he buy?
Lana71 [14]
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Good luck, hope that helped.
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Help with practice problem
fenix001 [56]

Answer:

y = 2x - 6

Step-by-step explanation:

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2 years ago
Please solve this literal equation for the variable "f"
Tatiana [17]
\frac{df+10}{6}= g

Now, multiply both sides by 6 and you get.....

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now, subtract 10 on both sides and you get.....

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f= \frac{6g-10}{d}

8 0
3 years ago
Trapezoid MNPQ is similar to Trapezoid RSTU. What is the length of the "x" on the misside side NP ? Also, what is the length of
ivolga24 [154]

Answer:

x =  15

y =  25

Step-by-step explanation:

Given

See attachment for MNPQ and RSTU

Required

Find x and y

To solve this question, we make use of equivalent ratios of corresponding side lengths.

The ratio of corresponding sides are:

MN : RS

NP : ST

PQ : TU

MQ : RU

From the attachment, we have:

MN : RS \to 18 : 30

NP : ST \to x : 25

PQ : TU \to 15 : y

To solve for x, we equate MN : RS and NP : ST

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Express as fraction

\frac{18 }{ 30 }= \frac{x }{ 25}

Make x the subject

x =  25 * \frac{18 }{ 30 }

x =  \frac{25 * 18 }{ 30 }

x =  \frac{450}{ 30 }

x =  15

To solve for y, we equate MN : RS and PQ : TU

18 : 30 = 15 : y

Express as fraction

\frac{18 }{ 30 }= \frac{15 }{ y}

Make y the subject

y = 15 * \frac{30 }{ 18 }

y =  \frac{15 *30}{ 18 }

y =  \frac{450}{ 18 }

y =  25

8 0
3 years ago
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