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damaskus [11]
3 years ago
9

Pls help me it's due today​

Mathematics
1 answer:
Dimas [21]3 years ago
8 0

Answer:

r³ + 15r² - 10r - 4

Step-by-step explanation:

First, note you can remove the brackets, in this case they contribute nothing at all.

Then, group the like terms and add them, e.g., we have 3r³ and -2r², they add up to r³.

Finally, order them from greatest power of r to smallest power of r.

That's all!

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Answer:

D

Step-by-step explanation:

Look at the coordinates of the new figure. Remember that coordinates are formatted so that the x comes first and then the y

7 0
3 years ago
How a bar model can be used to show a subtraction problem? 2 grade
lilavasa [31]
Lets say that you have 4-2=? you can use a bar model.... 

 {the stars are the bars}
 you have 4 total and now you need to subtract 2
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{ i just took away 2 and then you count the bars but in this model count the stars}
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Hope this helps!!! 

5 0
3 years ago
Read 2 more answers
Four emple yees can service 20
photoshop1234 [79]

Answer:

4

Step-by-step explanation:

Given that 20 / 5 = 4

It will take just about 4 hours (240 minutes).

Each car requires 1 hour to wash.

So, it will erase 1 hour.

I hope this helps. ❤

If this is wrong, please let me know.

3 0
3 years ago
What is 7√27+5√48 in simplified radical form?
Andreyy89
7√27 + 5√48

7 × 3√3 + 5√48

7 × 3√3 + 5 × 4√3

21√3 + 5 × 4√3

21√3 + 20√3

41√3      or 71.014

hope this helps, God bless!
3 0
4 years ago
How to answer this? A farmer had 455 ducks and chickens. He sold 2/5 of the ducks and bought another 104 chickens. As a result,
julia-pushkina [17]

Answer:

(a) 25

(b) $4816

Step-by-step explanation:

Let's say the starting amount of ducks is d, and the starting amount of chickens is c. Since there are only ducks and chickens, we can say that d + c= 455.

Next, the farmer sells 2/5 of the ducks, so we subtract 2/5 of the ducks so that the ending duck amount is d - (2/5)d = (3/5) d

After that, the farmer buys another 104 chickens, so we add 104 chickens to the current amount of chickens to get the ending chicken number as 104+c

Given the ending duck and chicken count, we can say that the ending farm animal count (we can represent this as a) is (3/5)d + 104 + c = a

The number of ducks is 2/3 the total number of animals at the end, so (3/5)d = (2/3)a

Let's list our equations out so it is easier to solve:

d+c = 455

(3/5)d + 104 + c = a

(3/5)d = (2/3)a

We have three equations and need to solve for three variables. One common variable in all three equations is d, so it might help if we put everything in terms of d.

Starting with d+c=455, if we subtract d from both sides, we get c=455-d. We can substitute this in the second equation to get

(3/5)d + 104 + 455 - d = a

-(2/5)d + 559 = a

(3/5)d = (2/3)a

Next, we can substitute for a. If we multiply both sides by 3 and then divide by 2 in (3/5)d = (2/3)a , we get

(9/10)d = a

Substitute that in to the second equation to get

-(2/5)d + 559 = (9/10) d

-(4/10)d + 559 = (9/10) d

add (4/10)d to both sides to isolate the variable and its coefficient

(13/10)d = 559

multiply both sides by (10/13) to isolate the coefficient

d = 430

Therefore, the starting number of ducks is 430 and the starting amount of chickens is 455-430 = 25

For (b), 2/5ths of the ducks are sold, so this is (430) * (2/5) = 172. Each duck is sold for 28 dollars, so this is 172*28=$4816 as the total price

7 0
3 years ago
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