The probability would be 39.9%
The given probability states that 39.9% of the 3 years olds are in daycare. Therefore, it would be obvious to assume that if you randomly selected a 3 year old, that would be the probability that he/she is in daycare.
Answer: search it up
Step-by-step explanation:
Answer:
x,y = 13/3, -10/3
Step-by-step explanation:
8x+8y=8
8x+2y=28 Subtract eq1 by eq 2
6y=-20
y=-20/6 y = -10/3
8x - 80/3=8
8x=34 2/3
x=4 1/3
x=13/3
Hope this helps plz hit the crown :D
