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3 years ago

Which ordered pairs are solutions to the inequality 2x - y > -4? Check all that apply.

Mathematics

1 answer:

JulsSmile [24]3 years ago

4 0

Answer:

(1,-6)

(-2,-5)

(8,2)

(4,0)

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ests for tuberculosis like all other diagnostic tests are not perfect. QFT-G is one of such tests for tuberculosis. Suppose that

Brut [27]

Answer:

P(POSc/Sc)

Step-by-step explanation:

As,

POS= Test has positive results

and

S=Adult has tuberculosis.

The test correctly identifies 74.6% of the time adults with a tuberculosis and correctly identifies those without tuberculosis 76.53% of the time.

In the above statement 76.53% describes the probability of adult who don't have tuberculosis gets the negative results as test is correctly identifying.

So, getting negative results means that not positive results and for this event the notation of complement POSc is used. Also, not having tuberculosis can be denoted as Sc. So,

POSc= Test has negative results

Sc=Adult hasn't tuberculosis

Thus, P(POSc/Sc) depicts the probability of adults not having tuberculosis gets correct results.

Hence, P(POSc/Sc)=76.53%

3 0

3 years ago

A woman pushes a lawn mower with a constant force of 112 Newtons at an angle of 37◦ with respect to the horizontal. The lawn mow

user100 [1]

Answer:

1.0.024 hp

Step-by-step explanation:

We are given that

Constant force=F=112 N

$\theta=37^{\circ}$

Speed of lawn mower,v=20 cm/s= $20\times 10^{-2} m/s$

1 m=100 cm

1 hp=746 watt

We have to find the power output

Force applied by women on lawn mower= $Fcos\theta=112cos 37^{\circ}$

Force applied by women on lawn mower= $89.45$ N

Power output,P= $Fv$

Using the formula

Power output= $89.45\times 20\times 10^{-2}=17.89 watt$

Power output,P= $\frac{17.89}{746}=0.024$ hp

Hence, option 1 is true

5 0

4 years ago

Factor each expression by finding the GCF.

elena-14-01-66 [18.8K]

8(1+3) and that is that answer easy

4 0

3 years ago

Marcie bought a total of 20 used books and cds during a yard sale for a total of 54.50$. of books cost 1.50$ each and cds 5$ eac

melomori [17]

Let numbers of books be 'b' and numbers of CDs be 'c'

We can set up two equations:
Equation [1] ⇒ $b+c=20$
Equation [2] ⇒ $1.50b+5c=54.50$

We are solving for the number of books and the number of CDs bought

When we have two equations in terms of two different variables; $b$ and $c$ , that we need to solve, then this becomes a simultaneous equation problem.

First, rearrange Equation [1] to make either $b$ or $c$ the subject:
$b+c=20$
$b=20-c$

Then we substitute $b=20-c$ into Equation [2]
$1.50b+5c=54.50$
$1.50(20-c)+5c=54.50$
$30-1.50c+5c=54.50$
$5c-1.5c=54.50-30$
$3.5c=24.50$
$c=7$

Now we know the value of $c$ which is $c=7$ , substitute this value into $b=20-c$ we have $b=20-7=13$

Answer:
Numbers of books = 13
Numbers of CDs = 7

5 0

4 years ago

Boris buys candy that costs $7 per pound. He will spend at least $63 on candy. What are the possible numbers of pounds he will b

IgorLugansk [536]

Answer:

Anything above 9

Step-by-step explanation:

63/7=9

5 0

3 years ago