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mestny [16]
3 years ago
6

Need help asap will give brain and all non helpful answers will be reported

Mathematics
1 answer:
jonny [76]3 years ago
5 0

Answer:

Local max is .5

Step-by-step explanation:

The local maximum is for x values between 2 and 4

It looks like the x value is 2.5 and the y value is .5


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$46 shoes; 2.9% tax some one please help me and i'm new in this site
ZanzabumX [31]
If you would like to know the value of the 2.9% tax, you can calculate this using the following steps:

2.9% tax of $46 shoes = 2.9% * 46 = 2.9/100 * 46 = $1.334

If you would like to know what is the whole price you have to pay for the shoes (including the tax), you have to add $46 and $1.334:

$46 + $1.334 = $47.334
8 0
3 years ago
Help Me On These Please
RoseWind [281]
#1 is true. The term they have in common is y with an invisible coefficient in-front of the second y term

#2 has zero like terms. 15 has no variable, and the other terms have different variables.

#3 has two like terms, that’s 9 and 8 which add to equal 17. The answer is 3x + 17 aka D.

#4 has two like terms, the numbers with the variable ‘n’. 4n + 7n = 11n. Your answer is 11n + 12 aka D
7 0
3 years ago
What is (f - g)(x)?<br>f(x) = 5x<br>g(x) = 3x2 - 8x​
erma4kov [3.2K]

Answer:

(5x)-(3x^2-8x)=-3x^2+13x

Step-by-step explanation:

(f-g)(x)=f(x)-g(x)

Using this, we can subtract and find the answer.

(5x)-(3x^2-8x)=-3x^2+13x

6 0
2 years ago
Pls help oooooooooooooopoo
grigory [225]

9514 1404 393

Answer:

  140°

Step-by-step explanation:

Angles 1 and 3 are "corresponding" angles, so are congruent.

  ∠1 = ∠3

  20x +60 = 30x +20

  40 = 10x . . . . . . . . . . . . subtract 20x+20

  4 = x . . . . . . . . . . . . . . divide by 10

  ∠1 = 20x +60 = 20(4) +60 = 80 +60

  ∠1 = 140°

3 0
3 years ago
Read 2 more answers
Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL
Tems11 [23]

Answer:

Yes they are

Step-by-step explanation:

In the triangle JKL, the sides can be calculated as following:

  • J(2;5); K(1;1)

             => JK = \sqrt{(1-2)^{2} + (1-5)^{2}  } = \sqrt{(-1)^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • J(2;5); L(5;2)

             => JL = \sqrt{(5-2)^{2} + (2-5)^{2}  } = \sqrt{3^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • K(1;1); L(5;2)

             =>  KL = \sqrt{(5-1)^{2} + (2-1)^{2}  } = \sqrt{4^{2}+1^{2}  } = \sqrt{1+16}=\sqrt{17}

In the triangle QNP, the sides can be calculate as following:

  • Q(-4;4); N(-3;0)

             => QN = \sqrt{[-3-(-4)]^{2} + (0-4)^{2}  } = \sqrt{1^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • Q (-4;4); P(-7;1)

   => QP = \sqrt{[-7-(-4)]^{2} + (1-4)^{2}  } = \sqrt{(-3)^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • N(-3;0); P(-7;1)

             =>  NP = \sqrt{[-7-(-3)]^{2} + (1-0)^{2}  } = \sqrt{(-4)^{2}+1^{2}  } = \sqrt{16+1}=\sqrt{17}

It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP

=> They are congruent triangles

7 0
3 years ago
Read 2 more answers
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