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3 years ago

Need help asap will give brain and all non helpful answers will be reported

Mathematics

1 answer:

jonny [76]3 years ago

5 0

Answer:

Local max is .5

Step-by-step explanation:

The local maximum is for x values between 2 and 4

It looks like the x value is 2.5 and the y value is .5

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What are the zeros of the function represented by the quadratic expression 2x^2-5x-3

emmasim [6.3K]

2x2-5x-3=0

Two solutions were found :

x = -1/2 = -0.500

x = 3

Step by step solution :

Step  1  :

Equation at the end of step  1  :

(2x2 - 5x) - 3 = 0

Step  2  :

Trying to factor by splitting the middle term

2.1     Factoring  2x2-5x-3

The first term is,  2x2  its coefficient is  2 .
The middle term is,  -5x  its coefficient is  -5 .
The last term, "the constant", is  -3

Step-1 : Multiply the coefficient of the first term by the constant   2 • -3 = -6

Step-2 : Find two factors of  -6  whose sum equals the coefficient of the middle term, which is   -5 .

3 0

3 years ago

Find the center of a circle with the equation: x2 y2−32x−60y 1122=0 x 2 y 2 − 32 x − 60 y 1122 = 0

mixas84 [53]

The equation of a circle exists:

$$(x-h)^2 + (y-k)^2 = r^2$ , where (h, k) be the center.

The center of the circle exists at (16, 30).

<h3>What is the equation of a circle?</h3>

Let, the equation of a circle exists:

$$(x-h)^2 + (y-k)^2 = r^2$ , where (h, k) be the center.

We rewrite the equation and set them equal :

$$(x-h)^2 + (y-k)^2 - r^2 = x^2+y^2- 32x - 60y +1122=0$

$$x^2 - 2hx + h^2 + y^2 - 2ky + k^2 - r^2 = x^2 + y^2 - 32x - 60y +1122 = 0$

We solve for each coefficient meaning if the term on the LHS contains an x then its coefficient exists exactly as the one on the RHS containing the x or y.

-2hx = -32x

h = -32/-2

⇒ h = 16.

-2ky = -60y

k = -60/-2

⇒ k = 30.

The center of the circle exists at (16, 30).

To learn more about center of the circle refer to:

brainly.com/question/10633821

#SPJ4

7 0

2 years ago

Lol help now files just type it

insens350 [35]

Answer:

2 = 4/2

Step-by-step explanation:

Well the one for the 2 wholes, Since 2 wholes equal 4/2

because 4/2 simplified is 2 whole it I believe would be 4/2

6 0

3 years ago

Read 2 more answers

What is 1/8 converted into a fraction?

AVprozaik [17]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

The population, P(t), of China, in billions, can be approximated by1 P(t)=1.394(1.006)t, where t is the number of years since th

vitfil [10]

Answer:

At the start of 2014, the population was growing at 8.34 million people per year.

At the start of 2015, the population was growing at 8.39 million people per year.

Step-by-step explanation:

To find how fast was the population growing at the start of 2014 and at the start of 2015 we need to take the derivative of the function with respect to t.

The derivative shows by how much the function (the population, in this case) is changing when the variable you're deriving with respect to (time) increases one unit (one year).

We know that the population, P(t), of China, in billions, can be approximated by $P(t)=1.394(1.006)^t$

To find the derivative you need to:

$\frac{d}{dt}\left(1.394\cdot \:1.006^t\right)=\\\\\mathrm{Take\:the\:constant\:out}:\quad \left(a\cdot f\right)'=a\cdot f\:'\\\\1.394\frac{d}{dt}\left(1.006^t\right)\\\\\mathrm{Apply\:the\:derivative\:exponent\:rule}:\quad \frac{d}{dx}\left(a^x\right)=a^x\ln \left(a\right)\\\\1.394\cdot \:1.006^t\ln \left(1.006\right)\\\\\frac{d}{dt}\left(1.394\cdot \:1.006^t\right)=(1.394\cdot \ln \left(1.006\right))\cdot 1.006^t$

To find the population growing at the start of 2014 we say t = 0

$P(t)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^t\\P(0)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^0\\P(0)' = 0.00833901 \:Billion/year$

To find the population growing at the start of 2015 we say t = 1

$P(t)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^t\\P(1)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^1\\P(1)' = 0.00838904 \:Billion/year$

To convert billion to million you multiple by 1000

$P(0)' = 0.00833901 \:Billion/year \cdot 1000 = 8.34 \:Million/year \\P(1)' = 0.00838904 \:Billion/year \cdot 1000 = 8.39 \:Million/year$

6 0

3 years ago