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Mandarinka [93]
3 years ago
12

(-2g^3h)(-3gj^4)^2(-ghj)^2

Mathematics
1 answer:
ratelena [41]3 years ago
4 0

QUESTION -

(-2g^3h)(-3gj^4)^2(-ghj)^2

ANSWER -

−18g^7h^3j^10


Hope i helped have a wonderful day..can i get Brainliest please and thank you...


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One of the roots of the equation 3x^2+7x−q=0 is −5. Find the other root and q.
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Answer: The answer is \textup{The other root is }\dfrac{8}{3}~\textup{and}q=40.Step-by-step explanation:  The given quadratic equation is[tex]3x^2+7x-q=0\\\\\Rightarrow x^2-\dfrac{7}{3}x-\dfrac{q}{3}=0.

Also given that -5 is one of the roots, we are to find the other root and the value of 'q'.

Let the other root of the equation be 'p'. So, we have

p-5=-\dfrac{7}{3}\\\\\\\Rightarrow p=5-\dfrac{7}{3}\\\\\\\Rightarrow p=\dfrac{8}{3},

and

p\times(-5)=-\dfrac{q}{3}\\\\\\\Rightarrow \dfrac{8}{3}\times 5=\dfrac{q}{3}\\\\\\\Rightarrow q=40.

Thus, the other root is \dfrac{8}{3} and the value of 'q' is 40.

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kvasek [131]

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I KNOWW THE ANSWER!!

Step-by-step explanation:

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3 years ago
Identify two tables which represent quadratic relationships
lord [1]

Answer:

Tables 3 and 5

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How do you solve for y in the equation: <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7By%7D%20%3Dy-6" id="TexFormula1" title
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y can be

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