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4 years ago

Question 1

Physics

1 answer:

solmaris [256]4 years ago

8 0

Answer:

4.0 m/s²

Explanation:

Draw two free body diagrams, one for the cart and one for the hanging mass.

The cart has one force acting on it in the x direction: tension to the right.

The hanging mass has two forces acting on it in the y direction: tension up and weight down.

The hanging mass accelerates downward, so if we take up to be positive, then the acceleration is negative.

Apply Newton's second law to the hanging mass:

∑F = ma

T − m₂g = m₂(-a)

T − m₂g = -m₂a

Apply Newton's second law to the cart:

∑F = ma

T = m₁a

Substitute and solve for a:

m₁a − m₂g = -m₂a

m₁a + m₂a = m₂g

(m₁ + m₂) a = m₂g

a = m₂g / (m₁ + m₂)

Given m₁ = 2.3 kg and m₂ = 1.6 kg:

a = (1.6 kg × 9.8 m/s²) / (2.3 kg + 1.6 kg)

a = 4.0 m/s²

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What is the acceleration of a 7 kg mass if the force of 70 N is used to move it toward the Earth?

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Explanation:

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3 years ago

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3 years ago

A bullet of mass m=26g is fired into a wooden block of mass M=4.7kg. The block is attached to a string of length 1.5m. The bulle

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Answer:

u = 449 m/s

Explanation:

Given,

Mass of the bullet, m = 26 g

Mass of the wooden block,M = 4.7 Kg

height of the block,h = 0.31 m

initial speed of the block, u = ?

Using conservation of energy

$(M+ m)gh = \dfrac{1}{2}(M+m)v^2$

$gh = \dfrac{1}{2}v^2$

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Now, using conservation of momentum to calculate the speed of the bullet.

m u + M u' = (M+m)v

m u = (M+m)v

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u = 449 m/s

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3 years ago

Two water jets are emerging from a vessel at a height of 50 centimeters and 100 centimeters. If their horizontal velocities at t

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For t1:

t1 = square root of 2h1 / g = square root of 2 * 0.5 / 9.8 = 0.319 sec

For t2:

t2 = sqaure root of 2h2 / g = square root of 2 * 1.0 / 9.8 = 0.451 sec

Wherein:
t = time(s) for the vertical movement
h= height
g = gravity (using the standard 9.8 m/sec measurement)

d1 = 1*0.319 = 0.319 m
d2 = 0.5 * 0.451 = 0.225 m

Where:

d = hor. distance

ratio = d1:d2
= 0.319 : 0.225
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The answer is 3.19 : 2.25

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3 years ago

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