How much work did the movers do (horizontally) pushing a 170-kg crate 10.2 m across a rough floor without acceleration, if the e
1 answer:
Answer:
Work done, W = 10195.92 Joules
Explanation:
Given that,
Mass of the crate, m = 170 kg
Distance, d = 10.2 m
The coefficient of friction,
Let W is the work done by the mover. It is given by in terms of coefficient of friction as :
W = 10195.92 Joules
So, the work done by the mover is 10195.92 Joules. Hence, this is the required solution.
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Answer:
The time elapsed at the spacecraft’s frame is less that the time elapsed at earth's frame
Explanation:
From the question we are told that
The distance between earth and Retah is
Here c is the peed of light with value
The time taken to reach Retah from earth is
The velocity of the spacecraft is mathematically evaluated as
substituting values
The time elapsed in the spacecraft’s frame is mathematically evaluated as
substituting value
=>
So The time elapsed at the spacecraft’s frame is less that the time elapsed at earth's frame