How much work did the movers do (horizontally) pushing a 170-kg crate 10.2 m across a rough floor without acceleration, if the e
1 answer:
Answer:
Work done, W = 10195.92 Joules
Explanation:
Given that,
Mass of the crate, m = 170 kg
Distance, d = 10.2 m
The coefficient of friction,
Let W is the work done by the mover. It is given by in terms of coefficient of friction as :
W = 10195.92 Joules
So, the work done by the mover is 10195.92 Joules. Hence, this is the required solution.
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