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Sergio039 [100]
3 years ago
14

How much work did the movers do (horizontally) pushing a 170-kg crate 10.2 m across a rough floor without acceleration, if the e

ffective coefficient of friction was 0.60?
Physics
1 answer:
zhannawk [14.2K]3 years ago
5 0

Answer:

Work done, W = 10195.92 Joules

Explanation:

Given that,

Mass of the crate, m = 170 kg

Distance, d = 10.2 m

The coefficient of friction, \mu=0.6

Let W is the work done by the mover. It is given by in terms of coefficient of friction as :

W=\mu mg\times d

W=0.6\times 170\times 9.8 \times 10.2

W = 10195.92 Joules

So, the work done by the mover is 10195.92 Joules. Hence, this is the required solution.

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