18. what Gives the missing value in 2/5 = x/30?

Use long division to convert the rational number to its equivalent decimal form. Upload a document showing all your work. 5/8

Hatshy [7]

Answer:

1.600

dont forget to press the crown:)

Step-by-step explanation:

We have the equation:

8 ÷ 5 = 1.600

Calculated to 3 decimal places.

1. 6 0 0

5 8. 0 0 0

− 5

3 0

− 3 0

0 0

− 0

0 0

− 0

0

7 0

3 years ago

Read 2 more answers

What is the value of t on the truss of the bridge?

IceJOKER [234]

Answer:

Step-by-step explanation:

t° + 55° = 90° (Exterior angle of a triangle is equal to the sum of the opposite interior angles.)

${t}^{o} + {55}^{o} = {90}^{o} \\ {t}^{o} = {90}^{o} - {55}^{o} \\ {t}^{o} = {35}^{o} \\$

7 0

2 years ago

Solve the linear system using substitution. Show your work. y = -3x + 3 4x +3y = -1

marishachu [46]

Sub y in the second equation by y in the first equation:
We get 4x+3(-3x+3)=-1
4x-9x+9=-1
-5x=-10
x=2
Sub in the first equation
y=-3(2)+3
y=-3

3 0

3 years ago

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Match each exponential function to the description of its percent rate of change.

dolphi86 [110]

Answer:

Given in order:

22% growth
12% growth
12% decay
20% decay

Step-by-step explanation:

The exponential function is in the form $f(x)=a(1+r)^x$

If r is positive (the number in the bracket is larger than 1), then it is exponential growth and if r is negative (the number in the bracket is less than 1), then it is exponential decay.

Growth or Decay by how much???

The amount that is greater than/less than 1

The first function's number inside the bracket is greater than 1 by 0.22 (22%). So it is "22% growth".
The second function's number inside the bracket is greater than 1 by 0.12 (12%). So it is "12% growth".
The third function's number inside the bracket is less than 1 by 0.12 (12%). So it is "12% decay".
The fourth function's number inside the bracket is less than 1 by 0.2 (20%). So it is "20% decay".

3 0

3 years ago

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Test the claim that the mean GPA of night students is larger than 2 at the .025 significance level. The null and alternative hyp

exis [7]

Answer:

$H_0: \, \mu = 2$ .

$H_1:\, \mu > 2$ .

Test statistics: $z \approx 2.582$ .

Critical value: $z_{1 - 0.025} \approx 1.960$ .

Conclusion: reject the null hypothesis.

Step-by-step explanation:

The claim is that the mean $\mu$ is greater than $2$ . This claim should be reflected in the alternative hypothesis:

$H_1:\, \mu > 2$ .

The corresponding null hypothesis would be:

$H_0:\, \mu = 2$ .

In this setup, the null hypothesis $H_0:\, \mu = 2$ suggests that $\mu_0 = 2$ should be the true population mean of GPA.

However, the alternative hypothesis $H_1:\, \mu > 2$ does not agree; this hypothesis suggests that the real population mean should be greater than $\mu_0= 2$ .

One way to test this pair of hypotheses is to sample the population. Assume that the population mean is indeed $\mu_0 = 2$ (i.e., the null hypothesis is true.) How likely would the sample (sample mean $\overline{X} = 2.02$ with sample standard deviation $s = 0.06$ ) be observed in this hypothetical population?

Let $\sigma$ denote the population standard deviation.

Given the large sample size $n = 60$ , the population standard deviation should be approximately equal to that of the sample:

$\sigma \approx s = 0.06$ .

Also because of the large sample size, the central limit theorem implies that $Z= \displaystyle \frac{\overline{X} - \mu_0}{\sigma / \sqrt{n}}$ should be close to a standard normal random variable. Use a $Z$ -test.

Given the observation of $\overline{X} = 2.02$ with sample standard deviation $s = 0.06$ :

$\begin{aligned}z_\text{observed}&= \frac{\overline{X} - \mu_0}{\sigma / \sqrt{n}} \\ &\approx \frac{\overline{X} - \mu_0}{s / \sqrt{n}} = \frac{2.02 - 2}{0.06 / \sqrt{60}} \approx 2.582\end{aligned}$ .

Because the alternative hypothesis suggests that the population mean is greater than $\mu_0 = 2$ , the null hypothesis should be rejected only if the sample mean is too big- not too small. Apply a one-sided right-tailed $z$ -test. The question requested a significant level of $0.025$ . Therefore, the critical value $z_{1 - 0.025}$ should ensure that $P( Z > z_{1 - 0.025}) = 0.025$ .

Look up an inverse $Z$ table. The $z_{1 - 0.025}$ that meets this requirement is $z_{1 - 0.025} \approx 1.960$ .

The $z$ -value observed from the sample is $z_\text{observed}\approx 2.582$ , which is greater than the critical value. In other words, the deviation of the sample from the mean in the null hypothesis is sufficient large, such that the null hypothesis needs to be rejected at this $0.025$ confidence level in favor of the alternative hypothesis.

3 0

3 years ago