It would be C. inherited characteristics
Answer : The concentration of
at equilibrium is 0 M.
Solution : Given,
Concentration of
= 0.0200 M
Concentration of
= 1.00 M
The given equilibrium reaction is,
![Fe^{3+}(aq)+3C_2O_4^{2-}(aq)\rightleftharpoons [Fe(C_2O_4)_3]^{3-}(aq)](https://tex.z-dn.net/?f=Fe%5E%7B3%2B%7D%28aq%29%2B3C_2O_4%5E%7B2-%7D%28aq%29%5Crightleftharpoons%20%5BFe%28C_2O_4%29_3%5D%5E%7B3-%7D%28aq%29)
Initially conc. 0.02 1.00 0
At eqm. (0.02-x) (1.00-3x) x
The expression of
will be,
![K_c=\frac{[[Fe(C_2O_4)_3]^{3-}]}{[C_2O_4^{2-}]^3[Fe^{3+}]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5B%5BFe%28C_2O_4%29_3%5D%5E%7B3-%7D%5D%7D%7B%5BC_2O_4%5E%7B2-%7D%5D%5E3%5BFe%5E%7B3%2B%7D%5D%7D)

By solving the term, we get:

Concentration of
at equilibrium = 0.02 - x = 0.02 - 0.02 = 0 M
Therefore, the concentration of
at equilibrium is 0 M.
Strong electrolytes by definition are those compounds that completely dissociates into their component ions when dissolved in water. The chemical formula for the zinc fluoride is,
ZnF2
This means that each formula unit is composed of one atom of zinc and 2 atoms of fluoride. The ions comprising the unit are Zn²⁺ and F⁻. The dissociation is as shown below,
ZnF₂ --> Zn²⁺ + 2F⁻
When dissolved in water it is expected that the compound dissociates into three different ions, one Zn²⁺ and two F⁻.
This was clear chemical reaction. The Potassium Chlorate reacted with Oxygen in a combustion reaction to change the chemical structure so that it was able to react with Silver Nitrate.