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oee [108]
3 years ago
8

El NaCI corresponde a un elemento?

Chemistry
1 answer:
Schach [20]3 years ago
7 0

Answer:

Sodio (Na), elemento químico del grupo de los metales alcalinos (Grupo 1 [Ia]) de la tabla periódica. El sodio es un metal blanco plateado muy suave. El sodio es el metal alcalino más común y el sexto elemento más abundante en la Tierra, y comprende el 2,8 por ciento de la corteza terrestre.

Explanation:

Espero que esto ayude a marcar el MÁS CEREBRAL !!!

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What is the Na+ concentration in each of the following solutions:
iren [92.7K]

Sodium Sulfate = Na2(SO4) meaning there are two ions of Na+ in one mole of Sodium Sulfate the M stands for Molarity, defined as Molarity = (moles of solute)/(Liters of solution), So if the Na2SO4 solution is 3.65M that means one Liter of has 3.65 moles of Na2SO4, the stoichiometry of Na2SO4 shows that there would be two Na+ ions in solution for every one Na2SO4.

Therefore if 3.65 moles of Na2SO4 was to dissolve, it would produce 7.3 moles of Na+, and since this is still a theoretical solution, we can assume 1 L of solution.

Finally we find [Na+] = 2*3.65 = 7.3M

Use the same logic for parts b and c




5 0
3 years ago
How many kilograms of a fertilizer are made of pure P2O5 would be required to supply 1.69 kilogram of phosphorus to the soil?
Alekssandra [29.7K]

Answer:

3.89 kg P2O5 must be used to supply 1.69 kg Phosphorus to the soil.

Explanation:

The molecular mass of P2O5 is

P2 = 2* 31 =           62

O5 = 5 *<u> 16 =         80</u>

Molecular Mass = 142

Set up a Proportion

142 grams P2O5 supplies 62 grams of phosphorus

x    kg P2O5        supplies 1.69 kg of phosphorus

Though this might be a bit anti intuitive, you don't have to convert the units for this question. The ratio is all that is important.

142/x = 62/1.69            Cross multiply

142 * 1.69 = 62x           combine the left

239.98 = 62x               Divide by 62

239.98/62 = x

3.89 kg of P2O5 must be used.

3 0
3 years ago
A foce that pushes or pulls is known as​
Radda [10]

Answer:

Newton 3rd Law of Motion or the Law of Force Pairs

(An applied force)

3 0
3 years ago
Which of the following has six electrons in its valence shell?
Sergeu [11.5K]
Simple...

moving along the periodic table ---->>>

Oxygen has 6.

Nitrogen has 5.

Sodium has 1.

Neon has 8.

Thus, your answer, Oxygen.
6 0
3 years ago
Read 2 more answers
Which of the following aqueous solutions would have the highest boiling point? 3.0 M solution of molecular compound sucrose (C12
Ne4ueva [31]

Answer: option b) 3.0 M solution of ionic compound aluminum chloride (AlCl₃)


Explanation:


1) The solutions given are:


a) 3.0 M solution of molecular compound sucrose (C₁₂H₂₂O₁₁)


b) 3.0 M solution of ionic compound aluminum chloride (AlCl₃)


c) 3.0 M solution of ionic compound lithium bromide (LiBr)


d) 3.0 M solution of ionic compound calcium fluoride (CaF₂)


2) The elevation of the boiling point of a solution is a colligative property.


3) That means that the elevation of the boiling point depends on the number of solute particles in the solvent and not the identity per se of the solute particles.


4) The formula of the elevation of the boiling point, ΔTb is:


ΔTb = i × m × Kb.


Where:


i) i is the Van't Hoof constant and is equal to the number of particles for each molecule or unit formula.


If the compound is a molecule (covalent bond) i = 1, if the compound is ionic, i is the number of ions product of the dissociation (I will show you how to determine it for each of the compounds given).


ii) m is the molality of the solution (moles of solute per kg of solvent)


iii) Kb is the molality boiling constant. It is a constant for every solvent. It does not change with the solute.


4) For our four compounds, m and kb are egual, so you must analyze the i factor for each solution.


a) 3.0 M solution of molecular compound sucrose (C₁₂H₂₂O₁₁)


Since it is a molecular compound it does not dissociate and i = 1


b) 3.0 M solution of ionic compound aluminum chloride (AlCl₃)


Assume the ionic compound dissociates 100%. The for eveary unit of AlCl₃ there will be 4 ions. Those are 4 particles and means that i = 4.


c) 3.0 M solution of ionic compound lithium bromide (LiBr)


Assuming also 100% dissociation of this ionic compound, since every LiBr unit dissociates into two ions, i = 2.


d) 3.0 M solution of ionic compound calcium fluoride (CaF₂)


Following same reasoning, i = 3.


5) Conclusion: since the greatest i factor is 4, and given all the other factors equal, the 3.0 M solution of ionic compound aluminum chloride (AlCl₃), option b, would be the aqueous solutions with the highest boiling point,

8 0
3 years ago
Read 2 more answers
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