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BaLLatris [955]
3 years ago
5

Using rolle's theorem f(x)=sin(5x) [

"\frac{\pi }{5}" alt="\frac{\pi }{5}" align="absmiddle" class="latex-formula"> , \frac{2\pi }{5}}
Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
7 0

Step-by-step explanation:

f(x) = sin(5x)

  • f is both continuous and differentiable in [π/5, 2π/5], since its a simple trigonometric function.

f( \frac{\pi}{5} ) = sin(5 \times  \frac{\pi}{5} ) = sin(\pi) = 0 \\ f( \frac{2\pi}{5} ) = sin(5 \times  \frac{2\pi}{5} ) = sin(2\pi) = 0

Hence:

f(π/5)=f(2π/5)

<u>Rolle's</u><u> </u><u>Theorem</u><u>:</u>

There is at least one ξ in [π/5, 2π/5], such as: f'(ξ)=0

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