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BlackZzzverrR [31]
2 years ago
12

What is the slope of the line shown below (6, 6) (1, -4)

Mathematics
2 answers:
snow_lady [41]2 years ago
8 0
Answer:

2

Step-by-step explanation:

To find the slope of a line, you must get two points off the line

Two points will be: (6, 6) and (1, -4)

Then use the Slope-Formula to solve for the slope of the line

m = slope
m = y2-y1/x2-x1
m = -4-6/1-6
m = -10/-5
m = 10/5
m = 2

The Slope of the line is 2
MatroZZZ [7]2 years ago
8 0

Answer:

2

Step-by-step explanation:

if you're looking at the table and you heard of rise/run, your rise is -10 if you go down from (6,6) and -5 if you go left to reach (1,-4). That will give you -10/-5 which gives you a positive 2. it would be the same if you went up 10 from (1,-4) and then 5 right to reach (6,6).

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Jocelyn’s plane travelled 500 mph for 7.3 hours. How far did her plane travel?
kogti [31]

Answer:

Jocelyn's plane travelled 3650 miles.

Step-by-step explanation:

mph stands for miles per hour.

Let's set up an equation.

total miles = speed(hours)

Jocelyn's plane travelled 500 mph for 7.3 hours.

total miles = 500(7.3)

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Jocelyn's plane travelled 3650 miles.

Hope this helps!

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What is a prime number.?
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Step-by-step explanation:

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Makenzie leaves her home at 10am. She has to be at her grandmother's house, which is 42 miles away. The
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will take approximately 1-2 hours or even longer

7 0
3 years ago
44. Express each of these system specifications using predicates, quantifiers, and logical connectives. a) Every user has access
DENIUS [597]

Answer:

a. ∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))

b. FileSystemLocked → ∀x Access(x, SystemMailbox)

c. ∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))

d. ∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

Step-by-step explanation:

a)  

Let the domain be users and mailboxes. Let User(x) be “x is a user”, let Mailbox(y) be “y is a mailbox”, and let Access(x, y) be “x has access to y”.  

∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))  

(b)

Let the domain be people in the group. Let Access(x, y) be “x has access to y”. Let FileSystemLocked be the proposition “the file system is locked.” Let System Mailbox be the constant that is the system mailbox.  

FileSystemLocked → ∀x Access(x, SystemMailbox)  

(c)  

Let the domain be all applications. Let Firewall(x) be “x is the firewall”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”.  

∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))  

(d)

Let the domain be all applications and routers. Let Router(x) be “x is a router”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”. Let ThroughputNormal be “the throughput is between 100kbps and 500 kbps”. Let Functioning(y) be “y is functioning normally”.  

∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

4 0
3 years ago
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