Answer:
d.0.48
Explanation:
When a population is in Hardy Weinberg equilibrium the <u>genotypic </u>frequencies are:
freq (AA) = p²
freq (Aa) = 2pq
freq (aa) = q²
<em>p</em> is the frequency of the dominant <em>A</em> allele and <em>q</em> is the frequency of the recessive <em>a</em> allele.
In this population of 100 individuals, 84 martians have the dominant phenotype and 16 have the recessive phenotype.
Therefore:
q²=16/100
q² = 0.16
q=√0.16
q = 0.4
And p+q=1, so:
p = 1 - q
p = 1-0.4
p = 0.6
The frequency of heterozygotes is:
freq (Aa) = 2pq = 2 × 0.4 × 0.6
freq (Aa) = 0.48
There are 5 steps of the scientific method
1. Make a question
2. Do some research for that question.
3. Hypothesis ( guess what might happen during the experiment)
4. Test and Collect Data
5. Conclusion ( what you learned from the experiment)
The most common parasitic worm is the ringworm, which can be found from the intestines of cats, fish, rodents and other small mammals. In other rare cases, humans. This is instinctive Behavior!
Hope This Helps!
