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Law Incorporation [45]
3 years ago
14

The table below shows the predicted number of words Janae can type, y, in x minutes. Time (x, in minutes) Words Typed (y) 5 150

10 300 15 450 20 600 Which describes the pattern in the table? A. Janae types 25 words each minute. B. Janae types 30 words each minute. C. Janae types 145 words each minute. D. Janae types 150 words each minute.
Mathematics
1 answer:
NNADVOKAT [17]3 years ago
3 0

Answer:

its c

Step-by-step explanation:

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HELP!!!
juin [17]
E. 5x+3 = 28
5x = 28 - 3
Divide by 5
Final answer = 5

F. 3x-9 = 18
3x = 18 + 9
18 + 9 = 27
Divide by 3
Final answer: 9

G. 8x-1=7
8x = 7 + 1
7 + 1 = 8
8x = 8
Divide by 8
Final answer: 1

H. 3x+5 = 10
3x = 10 - 5
10 - 5 = 5
Divide by 3
Final answer: 5/3

i. 13 + 7x = -1
7x = -1 - 13
-1 - 13 = -14
Divide by 7
Final answer: -2

j. 14 = 3x + 5
-3x + 14 = 5
-3x = 5 - 14
-3x = -9
Divide by - 3
Final answer: 3

K. 4x - 7 = -13
4x = -13 + 7
4x = -6
Divide by 4
Final answer: -3/2

l. -3 = 2x+ 9
-2x - 3 = 9
-2x = 9 + 3
9 + 3 = 12
2x = 12
Divide it by -2
Final answer: -6


6 0
3 years ago
Read 2 more answers
(problem 83)
AVprozaik [17]

To find the derivative of this function, there is a property that we should know called the Constant Multiple Rule, which says:

\dfrac{d}{dx}[cf(x)] = cf'(x) (where c is a constant)


Remember that the derivative of \csc(x) is -\csc(x)\cot(x). However, you may notice that we are finding the derivative of \dfrac{1}{2}\csc(2x), not \dfrac{1}{2} \csc(x). So, we are going to have to use the chain rule. To complete the chain rule for the derivative of a trigonometric function (in layman's terms) is basically the following: First, complete the derivative of the trig function as you would if what was inside the trig function is x. Then, take the derivative of what's inside of the trig function and multiply it by what you found in the first step.


Let's apply that to our problem. Right now, I am not going to worry about the \dfrac{1}{2} at the front of the equation, since we can just multiply it back in at the end of our problem. So, let's examine \csc(2x). We see that what's inside the trig function is 2x, which has a derivative of 2. Thus, let's first find the derivative of \csc(2x) as if 2x was just x and then multiply it by 2.


The derivative of \csc(2x) would first be -\cot(2x)\csc(2x). Multiplying it by 2, we get our derivative of -2\cot(2x)\csc(2x). However, don't forget to multiply it by the \dfrac{1}{2} that we removed near the beginning. This gives us our final derivative of -\cot(2x)\csc(2x).


Remember that we now have to find the derivative at the given point. To do this, simply "plug in" the point into the derivative using the x-coordinate. This is shown below:

-\cot[2(\dfrac{\pi}{4})]\csc[2(\dfrac{\pi}{4})]

-\cot(\dfrac{\pi}{2})\csc(\dfrac{\pi}{2})

-(0)(1) = \boxed{0}


Our final answer is 0.

3 0
3 years ago
You have three items on your menu: pasta for $12, pizza for $15, and salad for $10. What is the average price of an item on your
dem82 [27]

Answer:

$13

Step-by-step explanation:

8 0
3 years ago
Do I write the equation y=mx+b
HACTEHA [7]
Steps:
1. 6x=4y + 7
2. You have to write it in slope intercept to get the slope and y-intercept.
3. Subtract 7 on both sides
4y= 6x-7
4. Divide everything by 4
5. Y= 3/2x + -7/4
6. Slope= 3/2 y-intercept= -7/4
6 0
3 years ago
The value of the dependent variable in a function is always ______ the value of the independent variable.
Nikolay [14]
The answer to this question is 2
6 0
3 years ago
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