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3 years ago

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Shortly before the 1932 presidential election, a national magazine conducted a telephone survey of voters.Based on the results o

f the survey, the magazine predicted that Herbert Hoover (republican) would beat Franklin Roosevelt (Democrat) by a landslide

2 answers:

statuscvo [17]3 years ago

7 0

Answer:

DATA GATHERING

Step-by-step explanation:

Shtirlitz [24]3 years ago

3 0

Wow that’s cool to know

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Please someone help me to prove this.

dem82 [27]

<h3><u>Answer</u> :</h3>

We know that,

$\dag\bf\:sin^2A=\dfrac{1-cos2A}{2}$

$\dag\bf\:sin2A=2sinA\:cosA$

<u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u>

<u>Now, Let's solve</u> !

$\leadsto\:\bf\dfrac{sin^2A-sin^2B}{sinA\:cosA-sinB\:cosB}$

$\leadsto\:\sf\dfrac{\frac{1-cos2A}{2}-\frac{1-cos2B}{2}}{\frac{2sinA\:cosA}{2}-\frac{2sinB\:cosB}{2}}$

$\leadsto\:\sf\dfrac{1-cos2A-1+cos2B}{sin2A-sin2B}$

$\leadsto\:\sf\dfrac{2sin\frac{2A+2B}{2}\:sin\frac{2A-2B}{2}}{2sin\frac{2A-2B}{2}\:cos\frac{2A+2B}{2}}$

$\leadsto\:\sf\dfrac{sin(A+B)}{cos(A+B)}$

$\leadsto\:\bf{tan(A+B)}$

5 0

3 years ago

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Maria makes a fruit salad. The table shows the amounts of different kinds of fruit that she uses.

Elena-2011 [213]

Your answer is 3 1/4

3 0

3 years ago

I need help with this plz help me fast!!

lesya692 [45]

The answer is A I believe

4 0

3 years ago

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Which irrational number is represented by point D?

Leno4ka [110]

Answer:

it is 182

Step-by-step explanation:

182= 13.49

162= 12.73

204= 14.28

221=14.87

7 0

3 years ago

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Which rules of exponents will be used to evaluate the expression. Check all that apply

julia-pushkina [17]

Hello!

The answer are:

- Product of powers.

- Power of a power.

- Negative exponents.

<h2>Why?</h2>

Let's solve it!

It's a math rule that we must solve first what's into a brake or parenthesis, so,

First: Product of powers $[(7)^{5}*(7)^{3}]$

According to the exponent's law, we have a product of powers case, so, we need to sum the exponents and keep the base

Exponents: 5 and 3

Base: 7

Applying it we have:

$(7)^{5+3}$

$(7)^{8}$

Then,

We have a power of a power case, which involves multiplying the exponents:

$[(7)^{5}*(7)^{3}]^{-4}$

Exponents: 3 and -4

Then,

$(7)^{8*-4}$

Finally, we can apply the negative exponents, the negative exponent's rules state that negative exponents are the reciprocal of the positive exponents,

So, we will have that:

$(7)^{-32}=\frac{1}{7^{32} }$

Have a nice day!

6 0

3 years ago

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