Answer:
The probability of the number of Protestants that were calm for 2 out of 3 days is 0.061.
Step-by-step explanation:
Represent the provided data as follows:
Compute the probability of the number of Protestants that were calm for 2 out of 3 days as follows:
The number of Protestants surveyed is, <em>n</em> (Protestants) = 99.
The number of Protestants who were calm for 2 days,
<em>n</em> (Protestants who were calm for 2 days) = 6
The required probability is:
Thus, the probability of the number of Protestants that were calm for 2 out of 3 days is 0.061.
<span>Let opposite ray be drawn for the base side ray of the given angle.
This gives angle 180° between these two rays.
Angle bisectors of the given angles 50°, 90°, and 150° make respectively half of these angles : 25° , 45° and 75° with the base ray.
Then measure of the angles between the bisectors of the given angles and the drawn opposite ray are 180°-25°=155°, 180°- 45° =135° and 180°- 75° = 105° respectively.</span>
Answer:x+85=x+105
x+x=105+85
2x=190
x=190/2
x=95
Step-by-step explanation:
Answer:
hi taxes was waa Bynum waa Hitachi waa hug
-12 + 5(3) = total yards at the end
So your answer would be 3 yards
