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Mark brainliest please
Answer:
10.69
Step-by-step explanation:
We must first know that the angle of refraction is given by the following equation:
n_water * sin (A_water) = n_air * sin (A_air)
where n is the refractive index, for water it is 1.33 and for air it is 1.
The angle (A) in the air is 22.8 °, and that of the water is unknown.
Replacing these values we have to:
1.33 * sin (A_water) = 1 * 0.387
sin (A_water) = 1 * 0.387 / 1.33
A_water = arc sin (0.2907) = 16.9 °
now for the tank depth:
h = D / tan (A_water)
D = 3.25
Replacing
h = 3.25 / tan 16.9 °
h = 10.69
Therefore the depth is 10.69 meters.
Answer:
<em>2,300,000pages report.</em>
Step-by-step explanation:
Given a USB drive with memory of 4.6*10⁶KB, in order to know the maximum number of pages a report can have so that it can be completely stored on the drive, the conversion factor must be used.
We must first understand that 1 page of a document uses up approximately 2kB of the storage.
Since 2kB = 1page
4.6*10⁶KB = x page
Cross multiply
2kB * x = 4.6*10⁶KB * 1
2x = 4.6*10⁶
x = 4.6*10⁶/2
x = 2.3*10⁶
x = 2,300,000
<em>Hence the maximum number of pages that the report can have so that it can be completely stored on a USB drive that holds 4.6*10⁶KB is approximately 2,300,000pages report.</em>
Answer:
155.3 m
Step-by-step explanation:
<u>We have:</u>
θ: is the angle measured from the vertical = 75 °
v = is the speed of the submarine = 10 m/s
t = 1 min
The deep of the front end of the submarine at the end of a 1-minute drive is given by the following ratio:
<u>Where:</u>
d: is the distance traveled by the submarine in 1 minute
x: is the deep to find
The distance, d, is:
Now, the deep is:
Therefore, the deep of the front end of the submarine at the end of a 1-minute drive is 155.3 m.
I hope it helps you!
Answer:
y = -5/2x - 13
Step-by-step explanation:
First, we have to find the slope of the original equation
Subtract 5x from both sides
5x + 2y = 1
- 5x - 5x
2y = -5x + 1
Divide both sides by 2
2y/2 = (-5x + 1)/2
y = -5/2x + 1/2
The slope of this equation is -5/2, so -5/2 has to be in our new parallel equation
y = -5/2x + b
Plug in the given x and y
-3 = -5/2(-2) + b
-3 = 10 + b
Subtract 10 from both sides
-3 = 10 + b
- 10 - 10
b = -13
This makes our equation: y = -5/2x - 13
